Solve PV=nRT for V on Venus at STP

[amiv4]

Homework Statement

The conditions of standard temperature and pressure STP are a temperature of 0.00 C and a pressure of 1.00 atm.

For a scientist on Venus, an absolute pressure of 1 Venusian-atmosphere is 92 Earth-atmospheres. Of course she would use the Venusian-atmosphere to define STP. Assuming she kept the same temperature, how many liters would 1 mole of ideal gas occupy on Venus?

The Attempt at a Solution

PV=nRT
(1/92 atm)V=1 mol(.08205746 (L atm)/(K mol))(273.15 C)
V=2062.086

but that isn't right

 

[D H]

The pressure at the surface of Venus is 92 atmospheres, not 1/92^nd of an atmosphere.