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footprints
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[tex]y=4x^2-8x-5[/tex] Find the coordinates of the turning point of the curve. Where do I even start?
Try to completting the square on the function
Oh Yes! Now that you guys mention that, I know what to do now Thanks!Since it's a parabola, that would be its vertex.
A quadratic equation is a polynomial equation of the second degree, meaning it contains one variable raised to the power of two. It can be written in the form ax^2 + bx + c = 0, where a, b, and c are constants and x is the variable.
To solve a quadratic equation, you can use the quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a. Simply plug in the values of a, b, and c from the equation and solve for x. You can also use factoring or completing the square methods.
The turning point of a quadratic equation is the highest or lowest point on the parabola that the equation forms. It is also known as the vertex of the parabola.
To find the coordinates of the turning point, you can use the formula x = -b / 2a to find the x-coordinate. Then, plug this value into the original equation to solve for the y-coordinate. The coordinates will be in the form (x, y).
Yes, most scientific or graphing calculators have a function to find the coordinates of the turning point. Simply enter the quadratic equation into the calculator and use the appropriate function to find the coordinates.