Solve Ratio of x:y:z for y/(x-z)=(y+x)/z=x/y

  • Thread starter Miike012
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In summary, the conversation discusses finding the ratios of x:y:z in the given equations. The solution involves solving for y and z in terms of x, and considering two cases. The final ratios are determined to be 2:1:1.
  • #1
Miike012
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Homework Statement



IF y/(x-z) = (y+x)/z = x/y
Find the ratio of x:y:z

My thoughts: I have to get y/(x-z) = (y+x)/z = x/y to have the ratio x:y:z somehow then solve...?



The Attempt at a Solution

 
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  • #2
Try the equations

y/(x-z)=x/y and (y+x)/z=x/y.

Solve for y and z in terms of x.

ehild
 
  • #3
Algebra Prob.. Help please.

Homework Statement



The question is...
If y/(x-z) = (x+y)/z = x/z,
Find the ratios of x:y:z.

Here is the website that has the solution to the problem, But I am not understanding the solution because they are leaving information out.
http://www.mathh3lp.webs.com/

1) How did they determine that the ratio is 2 just by adding the three?
2)How did they get to (x+y)/z = x/y = 2.
3) How did they get to y = -x, and y/(x-z) = x/y ?
 
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  • #4


Try to solve the problem yourself. See my answer to your previous thread about the same problem.

ehild
 
  • #5


I can't find the post...
I think you said...
y/(x-z) = x/y
(x+y)/z = x/y
And solve?
 
  • #6


Miike012 said:
I can't find the post...
I think you said...
y/(x-z) = x/y
(x+y)/z = x/y
And solve?

(I merged your two threads for you)
 
  • #7


Miike012 said:
1) How did they determine that the ratio is 2 just by adding the three?
Consider three equivalent fractions, like
1/3, 2/6, and 3/9.
Find [tex]\frac{the.sum.of.the.numerators}{the.sum.of.the.denominators}[/tex] . What can you say about the resulting fraction?

Miike012 said:
2)How did they get to (x+y)/z = x/y = 2.
Since it was determined that each ratio is equal to 2 (or 2:1), it was written out that
ratio #2 = ratio #3 = 2 in order to determine the ratio for x:y:z.

Miike012 said:
3) How did they get to y = -x, and y/(x-z) = x/y ?
Two cases were considered here. In the first case, x + y ≠ 0. In the second case, x + y = 0, or y = -x. Simple, really.
 

FAQ: Solve Ratio of x:y:z for y/(x-z)=(y+x)/z=x/y

What is the equation for solving the ratio of x:y:z?

The equation for solving the ratio of x:y:z is y/(x-z)=(y+x)/z=x/y.

How do you solve for the value of y in this ratio?

To solve for the value of y in this ratio, you can use algebraic manipulation to isolate y on one side of the equation. First, multiply both sides of the equation by z to eliminate the fractions. Then, distribute the z on the right side of the equation. Next, move all terms containing y to one side of the equation and all other terms to the other side. Finally, divide both sides by the coefficient of y to isolate y and solve for its value.

Can this ratio be simplified?

Yes, this ratio can be simplified by dividing each term by their greatest common divisor. This will result in a simplified ratio of (x-z):(y+x):x.

Is this equation valid for all values of x, y, and z?

No, this equation is only valid for values of x, y, and z that satisfy the condition of y not equaling x-z. If this condition is not met, the equation will result in a division by zero error.

What is the significance of solving for the ratio of x:y:z?

Solving for the ratio of x:y:z can provide useful information about the relative sizes or proportions of x, y, and z. This can be helpful in various fields such as finance, statistics, and science where understanding and comparing different quantities is important.

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