- #1
meganterre
- 2
- 0
1. A 6V battery is connected to a 1F capacitor and 3 resistors (R1=1, R2=4, R3=2) R1 is is series with the battery. A junction then appears after R1, which creates 3 different paths, 2 for each remaining resistor, and another for the capacitor. After a long time, what is the magnitude of the current that runs through the battery? (i hope my description is ok, I have no picture)
2. V=IR
3. I keep reading that after a long time, when the capacitor has been fully charged, there is no current in the circuit. But I don't think this can apply when it is in parallel with 2 other resistors? Will the current stop in the path that leads to the capacitor, but will it continue to flow through the other resistors? I am confused on this aspect of the problem. I previously was trying to solve by saying that there are 2 charge sources when fully charged, so that the total V = 12V, and then I would calculate the current based off of total resistance. Can it be done this way? Any advice is greatly appreciated! Thanks!
2. V=IR
3. I keep reading that after a long time, when the capacitor has been fully charged, there is no current in the circuit. But I don't think this can apply when it is in parallel with 2 other resistors? Will the current stop in the path that leads to the capacitor, but will it continue to flow through the other resistors? I am confused on this aspect of the problem. I previously was trying to solve by saying that there are 2 charge sources when fully charged, so that the total V = 12V, and then I would calculate the current based off of total resistance. Can it be done this way? Any advice is greatly appreciated! Thanks!