Solve Simple Inequality: x < 0 or x > 2

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In summary, the set of values of x for the inequality (x - 1/2)^2 > x + 1/4 is { x: x < 0 or x > 2 }. This can be found by completing the square and taking the absolute value of x - 1 to determine the two possible cases for x.
  • #1
Fernando Revilla
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I quote a question from Yahoo! Answers

Find the set of values of x for ( x - 1/2 )^2 > x + 1/4 . Answer: { x: x < 0 or x > 2 }
Please help me to show the solution...

I have given a link to the topic there so the OP can see my response.
 
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  • #2
We have $$\left (x - \frac{1}{2}\right )^2 > x + \frac{1}{4}\Leftrightarrow x^2-x+\frac{1}{4}>x + \frac{1}{4}\\\Leftrightarrow x^2-2x=0\Leftrightarrow x(x-2)>0$$
Then, $$x(x-2)>0\Leftrightarrow (x>0\wedge x-2>0)\vee(x<0\wedge x-2<0)\\\Leftrightarrow (x>0\wedge x>2)\vee(x<0\wedge x<2)\Leftrightarrow (x>2)\vee(x<0)$$
That is, $x$ is a solution of the inequality iff $x\in(-\infty,0)\cup (2,+\infty)$.

P.S. Sorry, I didn´t notice that this question had been already solved there. I might have to make an appointment to visit an Alzheimer's specialist.
 
  • #3
Fernando Revilla said:
...
P.S. Sorry, I didn´t notice that this question had been already solved there. I might have to make an appointment to visit an Alzheimer's specialist.

I've noticed sometimes the replies of others do not show up until after you have posted a response. So, you may put off that appointment for now. (Happy)
 
  • #4
I find that the most direct way to solve quadratic inequalities is to complete the square.

\(\displaystyle \displaystyle \begin{align*} \left( x - \frac{1}{2} \right) ^2 &> x + \frac{1}{4} \\ x^2 - x + \frac{1}{4} &> x + \frac{1}{4} \\ x^2 - 2x &> 0 \\ x^2 - 2x + (-1)^2 &> (-1)^2 \\ (x - 1)^2 &> 1 \\ |x - 1| &> 1 \\ x - 1 < -1 \textrm{ or } x - 1 &> 1 \\ x < 0 \textrm{ or } x &> 2 \end{align*}\)
 
  • #5


Sure, no problem! Let's break down the given inequality step by step.

First, let's expand the left side of the inequality using the FOIL method:
(x - 1/2)^2 = (x - 1/2)(x - 1/2) = x^2 - x + 1/4

Now, we can rewrite the original inequality as:
x^2 - x + 1/4 > x + 1/4

Next, let's subtract x + 1/4 from both sides of the inequality:
x^2 - 2x > 0

Now, we can factor the left side of the inequality:
x(x - 2) > 0

To solve for x, we need to find the values of x that make this inequality true. We can do this by considering two cases:

Case 1: x > 0
In this case, both x and x-2 are positive, so their product will also be positive. Therefore, any value of x greater than 0 will satisfy the inequality.

Case 2: x - 2 < 0
In this case, x is negative and x-2 is positive. Their product will be negative. Therefore, any value of x less than 0 will also satisfy the inequality.

Combining these two cases, we can conclude that the set of values of x that satisfy the inequality are:
{ x: x < 0 or x > 2 }

I hope this helps! Let me know if you have any further questions.
 

FAQ: Solve Simple Inequality: x < 0 or x > 2

What does the inequality x < 0 or x > 2 mean?

The inequality x < 0 or x > 2 means that the value of x is either less than 0 or greater than 2. In other words, x can be any number that falls outside the range of 0 to 2, including negative numbers and numbers larger than 2.

How do you solve the inequality x < 0 or x > 2?

To solve this inequality, you can break it down into two separate inequalities: x < 0 and x > 2. Then, you can solve each one individually. For x < 0, the solution set will be all negative numbers. For x > 2, the solution set will be all numbers larger than 2. So, the overall solution set for x < 0 or x > 2 will be the combination of these two sets.

What does the solution set for x < 0 or x > 2 look like on a number line?

The solution set for x < 0 or x > 2 will look like two separate intervals on a number line, with a gap in between them. The first interval will be all numbers to the left of 0 (not including 0), and the second interval will be all numbers to the right of 2 (not including 2). The two intervals will not overlap.

Can the solution set for x < 0 or x > 2 include 0 or 2?

No, the solution set for x < 0 or x > 2 does not include 0 or 2. This is because the inequality specifically states that x cannot equal 0 or 2, so these numbers are not included in the solution set.

How can I graph the solution set for x < 0 or x > 2?

To graph the solution set for x < 0 or x > 2, you can use a number line and plot the two intervals described in question 3. You can also shade the area between the two intervals to show that the solution set does not include any numbers within this gap. Alternatively, you can use set builder notation to represent the solution set as {x | x < 0 or x > 2}.

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