Solve Simple Trigo Probs: Minimum Value & Proving Sin Product

  • Thread starter ron_jay
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In summary, the minimum value of the expression 9tan^2 \theta + 4cot^2 \theta is 12, with equality holding when |\tan \theta|=\sqrt{\frac{2}{3}}. For the second problem, to prove that sin20.sin40.sin60.sin80 =3/16, we must first find the minimum value of the expression 9tan^2 \theta + 4cot^2 \theta, which is 12, by setting 3 tan x = 2 cot x. This allows us to solve for a value of \theta that makes the expression 0, and thus the minimum value is 12.
  • #1
ron_jay
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Help needed to solve these:

1)what is the minimum value of the expression 9tan^2 [tex]\theta[/tex] + 4cot^2 [tex]\theta[/tex] ?

2)Prove that sin20.sin40.sin60.sin80 =3/16
 
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  • #2
Please show us how you would approach each of these problems. We must see your work first, in order for us to provide tutorial help. We do not furnish answers to homework and coursework questions here on the PF.
 
  • #3
1. [tex]9 \tan^{2} \theta + 4 \cot^{2} \theta =(3 \tan \theta - 2 \cot \theta)^{2}+12 \geq 12[/tex] with equality holding when [tex]|\tan \theta|=\sqrt{\frac{2}{3}}[/tex] sorry i didn't see berkeman's post
 
  • #4
To add a little understanding to pardesi's post, he wrote the expression in the form [tex](3 \tan \theta - 2\cot \theta)^2 + 12[/tex] because even though cot and tan don't have minimum values, squares do (in the real numbers, but that's a different matter). 12 is a constant we can't change that. We know squares are more or equal to 0. So the smallest value would be if the square was 0.

So you set 3 tan x = 2 cot x. If you can find a solution, which pardesi did, then there is a value for which it is 0. Done :)
 

FAQ: Solve Simple Trigo Probs: Minimum Value & Proving Sin Product

What are the two simple trigo problems?

The two simple trigo problems are the sine and cosine problems.

What is the difference between sine and cosine?

Sine and cosine are both trigonometric functions, but they differ in their relationship to the sides of a right triangle. Sine is the ratio of the length of the opposite side to the length of the hypotenuse, while cosine is the ratio of the length of the adjacent side to the length of the hypotenuse.

How do you solve for sine and cosine?

To solve for sine and cosine, you need to know the measure of one angle and the length of at least one side of a right triangle. Then, you can use the trigonometric ratios (sine, cosine, and tangent) to determine the values of sine and cosine for that angle.

What is the unit of measurement for sine and cosine?

Sine and cosine are dimensionless quantities, meaning they have no units of measurement. They are simply ratios of lengths, so the units cancel out.

What are some real-world applications of sine and cosine?

Sine and cosine have many real-world applications, such as in navigation, surveying, and engineering. They are also used in physics and astronomy to calculate the motion of objects and the positions of celestial bodies.

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