Solve Solid Compressability Homework Problem Involving Copper Block

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In summary, the conversation is about a problem involving a copper block with given compressibility and density undergoing an isothermal pressure change. The questions ask for the amount of heat leaving the system, the work done on the block, and the change in internal energy. The solution involves finding the volume change and using it to calculate the work done. The assumption is made that the change in internal energy is 0 and heat is equal to negative work.
  • #1
dacruick
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Homework Statement



Hello, I have a problem involving a copper block of mass .25kg. They have a given compressibility due to pressure change, and compressibility due to temperature change. They give the density for copper as well. They tell you that the pressure changes from P1 --> P2 isothermally.

It then asks what the amount of heat leaving the system is
The work done on the copper block
and the total change in internal energy


Homework Equations






The Attempt at a Solution



what I've done already is figured out the volume change due to the pressure change.

Using this volume change I can theoretically find the work done using -nRT*ln(Vf/Vi). The only problem is I don't have a value for the moles. I could find it if i had the molar mass of copper, but I don't, and this is a practice exam problem.

If i assume that because temperature change is 0, the change in internal energy is 0. Then heat will equal negative work. but i have a strong feeling this is wrong.
 
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  • #2
In an isothermal process, the work done is simply the pressure times the change in volume, i.e.
[tex]
W = P\Delta V
[/tex]
Does that help?
 

FAQ: Solve Solid Compressability Homework Problem Involving Copper Block

How do I calculate the compressibility of a copper block?

To calculate the compressibility of a copper block, you will need to know the initial volume and final volume of the block, as well as the initial and final applied forces. You can use the formula B = (F2-F1)/(V2-V1) where B is the compressibility, F is the applied force, and V is the volume. Make sure to use consistent units throughout your calculations.

What is the unit of compressibility?

The unit of compressibility is typically measured in inverse pressure units, such as pascal^-1 or bar^-1. This represents the change in volume per unit applied force.

Can I use the same formula for all materials?

No, the formula for compressibility may vary depending on the material. For example, the compressibility of gases is calculated differently than the compressibility of solids. Make sure to research the specific formula for the material you are working with.

How does temperature affect the compressibility of a material?

Temperature can have a significant impact on the compressibility of a material. Generally, as temperature increases, the compressibility of a material also increases. This is because heat causes the molecules in the material to vibrate more, making it easier for them to move and change shape.

Can I use experimental data to determine the compressibility of a material?

Yes, experimental data can be used to determine the compressibility of a material. You can measure the volume and applied force of a material at different points and use the data to calculate the compressibility. However, it is important to make sure that the experimental conditions are controlled and consistent for accurate results.

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