MHB Solve sqrt (x+ a) = x −7 when a=-1

  • Thread starter Thread starter rebo1984
  • Start date Start date
AI Thread Summary
The equation sqrt(x - 1) = x - 7 is analyzed with a = -1. Substituting potential solutions, x = 5 yields an incorrect result, as 2 does not equal -2. Similarly, testing x = 10 also fails to satisfy the equation. The discussion concludes that there is no valid solution for the equation when a = -1. Therefore, the solution set is determined to be no solution.
rebo1984
Messages
18
Reaction score
0
Hi,

If a = -1, what is the solution set of the equation sqrt (x+ a) = x −7

{5}
{10}
{5, 10}
No solution(5,10) correct?

Thanks
 
Mathematics news on Phys.org
rebo1984 said:
Hi,

If a = -1, what is the solution set of the equation sqrt (x+ a) = x −7

{5}
{10}
{5, 10}
No solution(5,10) correct?

Thanks

What do you get when you substitute each potential solution into the original equation?
 
MarkFL said:
What do you get when you substitute each potential solution into the original equation?

It works out.
 
rebo1984 said:
It works out.

Let's try \(x=5\):

$$\sqrt{5-1}=5-7$$

$$2=-2$$

Is this true?
 
rebo1984 said:
It works out.
What "works out"? Which answer did you get?
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...

Similar threads

Replies
1
Views
1K
Replies
2
Views
1K
Replies
6
Views
1K
Replies
3
Views
1K
Replies
41
Views
5K
Replies
1
Views
1K
Replies
3
Views
4K
Back
Top