- #1
tarheelborn
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Homework Statement
Using summation by parts, find Sum[n/3^n].
Homework Equations
Sum[a_k*b_k] = s_n*b_(n+1) - Sum[s_k(b_(k+1)-b_k]
The Attempt at a Solution
Let a_k = 1/3^k and b_k = k. Then b_(k+1)-b_k = 1. But what is s_k? I know that it is 1/3 + 1/3^2 + 1/3^3 + ... but what is the general term? Thanks for your help.