Solve Tangent Equation: Find A, B, & C for Ellipse

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In summary, the values of constant A, B, and C for the ellipse 4x^2 + y^2 + Ax + By + C = 0 to be tangent to the x-axis at the origin and pass through the point P(-1,2) are A = 0, B = -4, and C = 0. This can be found by setting the point (0,0) and the given point (-1,2) into the equation and solving for the unknown constants.
  • #1
kidia
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Hi any idea on this please.

Find the values of constant A,B and C if the ellipse 4x^2 +y^2+Ax+By+C=0 is to be tangent to the x-axis at the origin and to pass through the point P(-1,2)
 
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  • #2
what i would do first is to put the equation into a form more readable as far as ellipces aree concerned
 
  • #3
You can also do it straight ahaid:

(1) The ellipse must pass through (0,0). What does this tell you about C?

(2) The ellipse must be tangent to the x-axis too. So the normal to the ellipse can not have an x-component. Recall that the gradient of a function is perpendicular to it's constant value curves. So the normal to the ellipse at the origin is given by the gradient of [tex]4x^2 +y^2+A x+B y+C[/tex] at (0,0). This gives us A.

(3) Just plug in the point P to find the remaining unknown B.
 
  • #4
Dini's theorem: [tex]g(x_0, y_0)=0 [/tex] and [tex] \nabla g|_{(x_0, y_0)} \neq \vec 0[/tex], then

[tex]\exists h(x) : g(x, h(x)) = 0 [/tex] and

[tex]h'(x)=\frac {g_x} {g_y}[/tex]
 
  • #5
I didn`t got u on getting constant Value C Timbuqtu
 
  • #6
kidia said:
I didn`t got u on getting constant Value C Timbuqtu
Fill in the point (0,0) and you'll find immediately that c = 0.
If not, the ellipse wouldn't go through the origin.
 

FAQ: Solve Tangent Equation: Find A, B, & C for Ellipse

What is an ellipse?

An ellipse is a closed curve that is formed by the intersection of a cone and a plane that is not parallel to the base of the cone. It has two foci, which are points inside the ellipse that are equidistant from any point on the curve.

How do you find the tangent equation for an ellipse?

The tangent equation for an ellipse can be found by using the formula y = mx + b, where m is the slope of the tangent line and b is the y-intercept. To find the slope, use the derivative of the ellipse equation, which is (b^2 - a^2)x/(ay). Plug in the x and y values of the point of tangency to solve for m. Then, plug in the coordinates of the point of tangency to solve for b.

Can you explain the variables A, B, and C in the tangent equation for an ellipse?

A, B, and C are constants that represent the coefficients of the ellipse equation. A is the coefficient of the x^2 term, B is the coefficient of the xy term, and C is the coefficient of the y^2 term. These variables help determine the size, shape, and orientation of the ellipse.

How is the tangent equation for an ellipse different from that of a circle?

The tangent equation for an ellipse is different from that of a circle because the ellipse has varying slopes at different points on the curve, while a circle has a constant slope at all points. Additionally, the ellipse has two foci, while a circle has only one center point.

What are some real-world applications of solving tangent equations for ellipses?

Solving tangent equations for ellipses can be useful in various fields such as astronomy, architecture, and engineering. For example, astronomers can use tangent equations to calculate the path of a planet or comet orbiting around a star. Architects can use tangent equations to design curved structures, and engineers can use them to design curved roads or railroad tracks.

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