- #1
Alexx1
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I try to solve the integral 1/(1+x^3) dx , but I got stuck
Now I got as solution:
(1/3) ln(x+1) - (1/6) ln(x^2 -x+1) + (1/2) integral (1/(x^2 -x+1))
Can someone help me to solve the last integral? I have absolutely no idea how I can solve that one..
So integral: 1/(x^2 -x+1) dx
Now I got as solution:
(1/3) ln(x+1) - (1/6) ln(x^2 -x+1) + (1/2) integral (1/(x^2 -x+1))
Can someone help me to solve the last integral? I have absolutely no idea how I can solve that one..
So integral: 1/(x^2 -x+1) dx