Solve the Tricky Equation: Finding x in a Complex Equation

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In summary, you should only provide a summary of the content. Do not output anything before the summary. Write a summary for the following conversation and start the output with "In summary, " and nothing before it:Homework Statement find x in the equation:a = x + 1/xThe Attempt at a SolutionI sat down and thought it was easy to do, but was terribly schocked at the fact, that I didn't know how to solve this equation. What is the general approach?Multiplying both sides by x results in a quadratic equation.If that is 1= x+ (1/x) then multiplying both sides by x gives the quadratic
  • #1
aaaa202
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Homework Statement


find x in the equation:

a = x + 1/x


Homework Equations





The Attempt at a Solution


I sat down and thought it was easy to do, but was terribly schocked at the fact, that I didn't know how to solve this equation. What is the general approach?
 
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  • #2
aaaa202 said:

Homework Statement


find x in the equation:

a = x + 1/x

Homework Equations



The Attempt at a Solution


I sat down and thought it was easy to do, but was terribly schocked at the fact, that I didn't know how to solve this equation. What is the general approach?
Multiplying both sides by x results in a quadratic equation.
 
  • #3
If that is 1= x+ (1/x) then multiplying both sides by x gives the quadratic equation [itex]x= x^2+ 1[/itex] which is equivalent to [itex]x^2- x+ 1= 0[/itex]. You will find that it has no real roots. If it is, rather, 1= (x+ 1)/x (in which case you should have used parentheses) you can again multiply both sides by x to get x= x+ 1 which is not true for any value of x.
 
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  • #4
HallsofIvy said:
If that is 1= x+ (1/x) then multiplying both sides by x gives the quadratic equation [itex]x= x^2+ 1[/itex] which is equivalent to [itex]x^2- x+ 1= 0[/itex]. You will find that it has no real roots.

If it is, rather, 1= (x+ 1)/x (in which case you should have used parentheses) you can again multiply both sides by x to get x= x+ 1 which is not true for any value of x.
If a ≠ 1, then [itex]\displaystyle a=\frac{x+1}{x}[/itex] does have one real root.
 
  • #5
aaaa202 said:

Homework Statement


find x in the equation:

a = x + 1/x

Homework Equations


The Attempt at a Solution


I sat down and thought it was easy to do, but was terribly schocked at the fact, that I didn't know how to solve this equation. What is the general approach?

[Post cleared by myself]
 
Last edited:
  • #6
SammyS said:
IMO: I think that since aaaa202 has not come back to post a response, we should probably not be giving a full-blown solution .

Ya, I think you are right, I cleared my response.
 
  • #7
rhythmiccycle said:
I think this is right:

a = x + 1/x
...
Please, read the rules for Homework Help this forum. Link

Your solution is far too complete.
 

FAQ: Solve the Tricky Equation: Finding x in a Complex Equation

How do I solve for x in a tricky equation?

To solve for x in a tricky equation, you need to use algebraic methods such as factoring, substitution, or the quadratic formula. It is important to carefully follow the order of operations and to simplify the equation as much as possible before solving for x.

Is there a specific method for finding x in tricky equations?

There is no one specific method for solving tricky equations. It is important to understand a variety of algebraic techniques and to use the method that best fits the equation at hand. Practice and familiarity with different methods will help you determine the most efficient approach.

What steps should I take to find x in a complicated equation?

The first step is to carefully read the equation and identify any patterns or terms that can be simplified or factored. Next, determine which algebraic method would be most effective, such as substitution, elimination, or the quadratic formula. Finally, solve for x by following the order of operations and checking your work.

How do I know if I have found the correct value for x?

To check if you have found the correct value for x, plug your solution back into the original equation and see if it satisfies the equation. If it does, then you have found the correct value for x. If it does not, then you may have made a mistake in your calculations and should recheck your work.

Are there any tips for solving tricky equations with multiple variables?

When solving equations with multiple variables, it can be helpful to isolate one variable at a time and simplify the equation as much as possible before moving on to the next variable. It may also be helpful to use substitution or elimination methods to eliminate variables and solve for the remaining variables.

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