Aaaaaaaah I have seen my sign error, guess I was tired, thanks though.ehild said:The result is not quite correct. Recall that ##x=-2y##, If y=1, x=-2, and if y=-1, x=2.
Also there is one more solution set, for ##z-2y=0##.
Well, z=2y also gives solutions. See @Ray Vickson's Post #33, he gave the full solution (although it is not allowed here).chwala said:What do you mean? I clearly said considering ##6z=0## from my working will give you the solution. Kindly note that there are two values for ##z## and clearly ##z-2y=0## will not give you the solution.
I find no offense with his solution, I found the solution he though gave other possible solutions which is OK, reading my post I was only interested in finding the solutions in the text, which I found... Nothing wrong with anyone giving more solutions, my thoughtsehild said:Well, z=2y also gives solutions. See @Ray Vickson's Post #33, he gave the full solution (although it is not allowed here).
It is the policy of this Forum that the Helper must not give full solution, unless the OP produced his one. You did not give the full solution yet.chwala said:I find no offense with his solution, I found the solution he though gave other possible solutions which is OK, reading my post I was only interested in finding the solutions in the text, which I found... Nothing wrong with anyone giving more solutions, my thoughts
There is only one solution, the whole set of possible x, y, z values.chwala said:noted...i am able to get the other solution, but i was interested in the solution that i found...thanks a lot guys...
I thought i had posted the solution, made some sign error... Unless you want me to post step by step which is time consuming, if you insist I will just highlight on the last steps leading to all the four possible solutions..StoneTemplePython said:I found another approach to solving this with elementary symmetric sums, plus a bit of linear algebra mixed in. If @chwala would perhaps post a full solution, I could post my solution approach.
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edit: maybe not. too many small bugs.
chwala said:I thought i had posted the solution, made some sign error... Unless you want me to post step by step which is time consuming, if you insist I will just highlight on the last steps leading to all the four possible solutions..
Whichever way you call it, x ,y, z may have different values as indicated by the four possible sets or rather values.ehild said:There is only one solution, the whole set of possible x, y, z values.
Can I have a look at your symmetric methodStoneTemplePython said:No worries. There were just too many small bugs in my solution so I'm not going to post it -- I wouldn't insist anything more from you.