- #1
Dustinsfl
- 2,281
- 5
Consider \(u_{tt} - u_{xx} = \sin(u)\). Let \(u(\xi) = u(x - ct)\).
How do we get \((1 - c^2)u_{\xi\xi} = \sin(u)\)?
\[
u_{\xi\xi} = u_{xx} - c^2u_{tt}
\]
Correct?
How do we get \((1 - c^2)u_{\xi\xi} = \sin(u)\)?
\[
u_{\xi\xi} = u_{xx} - c^2u_{tt}
\]
Correct?