Solve Underground Cable Reactive Power: 127MVAr

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In summary, the conversation discusses the calculation of total reactive power for a 10km underground 50Hz grid line with a capacitance of 400nF per phase. The calculation results in 127MVAr, but there is confusion regarding whether this is the power per phase or total reactive power. The conversation also mentions finding the charging current in each phase and the voltage difference on a 400kV 3-phase transmission line.
  • #1
Lunat1c
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Hello,

I just got a small question.

If a 50Hz grid line is carried underground for a distance of 10km. And it is also known that the capacitance is 400nF per phase per km. What is the total reactive power generated in the 10km length?

Then I could say that we have a total of 400nF * 10 = 4000nF per phase.

[tex] Power = \frac{V^2}{X_c} = \frac{400k^2}{\frac{1}{2 * \pi * 50 * 4000nF}} = 127MVAr. [/tex]

1. However, this is the power per phase isn't it? From my lecture notes it is the total reactive power however I can't figure out why.

2. Also, I'm trying to find the charging current in each phase of the line.

According to my lecturer power in each phase is the power I got earlier divided by 3, but the same capacitance is used if the formula I^2Xc is used.

Please help, this is really confusing me!
 
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  • #2
Anyone please?
 
  • #3
Lunat1c said:
Hello,

I just got a small question.

If a 50Hz grid line is carried underground for a distance of 10km. And it is also known that the capacitance is 400nF per phase per km. What is the total reactive power generated in the 10km length?

Then I could say that we have a total of 400nF * 10 = 4000nF per phase.

[tex] Power = \frac{V^2}{X_c} = \frac{400k^2}{\frac{1}{2 * \pi * 50 * 4000nF}} = 127MVAr. [/tex]

1. However, this is the power per phase isn't it? From my lecture notes it is the total reactive power however I can't figure out why.

2. Also, I'm trying to find the charging current in each phase of the line.

According to my lecturer power in each phase is the power I got earlier divided by 3, but the same capacitance is used if the formula I^2Xc is used.

Please help, this is really confusing me!

What are you using for the "voltage"? The voltage that is listed for a 3-phase line does not show up across each wire pair...
 
  • #4
Sorry, my mistake. The question says it's a "400kV grid line"
 
  • #5
Lunat1c said:
Sorry, my mistake. The question says it's a "400kV grid line"

So for a 400kV 3-phase transmission line, what is the voltage difference between each pair? See if the answer makes more sense now.
 
  • #6
I'm not sure I follow. I think I misunderstood the question to be honest. When you're told that a cable is a 400kV cable, what's the meaning of that exactly? I know that when it comes to 3 phase systems for example, when you're told that you have a 415V supply, that means that the line to line voltage is 415. However I'm unsure about this.
 

FAQ: Solve Underground Cable Reactive Power: 127MVAr

What is reactive power in underground cables?

Reactive power is the power that is consumed by inductive loads, such as underground cables, to create and maintain magnetic fields. It is not directly used for any useful work, but it is necessary for the proper functioning of the system.

Why is it important to solve reactive power in underground cables?

Solving reactive power in underground cables is important because it can help improve the efficiency and reliability of the power system. Excessive reactive power can lead to voltage drops and power losses, which can cause blackouts and other power quality issues.

How is underground cable reactive power calculated?

Underground cable reactive power is typically calculated using mathematical formulas that take into account the cable's parameters, such as length, diameter, and insulation type. These calculations are important for determining the appropriate size and type of cables to use in a power system.

What are some methods for solving underground cable reactive power?

There are several methods for solving underground cable reactive power, including using power factor correction devices, installing capacitors or reactors, and implementing voltage control strategies. These methods can help reduce the reactive power demand and improve the overall power system performance.

How can solving underground cable reactive power benefit the power system?

Solving underground cable reactive power can have several benefits for the power system, such as reducing energy losses, improving voltage stability, and increasing the capacity of the system. It can also help reduce the cost of electricity for consumers and improve the overall reliability of the power supply.

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