Solve V1=(V2-u)/(1-uV2/C2) for V2

  • MHB
  • Thread starter jhanson58
  • Start date
In summary, the problem is that the number 1.999999... is pronounced as "one thousand nine hundred ninety-nine thousand nine hundred ninety-nine", which is incorrect.
  • #1
jhanson58
3
0
I am trying to understand my math problem. I know what an exponent is. But what does it mean when X 2 you have a little 2 in the lower right hand corner.

V1=V2-u/1-uV2/C2 Solve for V2 How do I go about doing this.
 
Last edited:
Mathematics news on Phys.org
  • #2
jhanson58 said:
I am trying to understand my math problem. I know what an exponent is. But what does it mean when X 2 you have a little 2 in the lower right hand corner.

V1=V2-u/1-uV2/C2 Solve for V2 How do I go about doing this.

Welcome to MHB, jhanson58! :)

A little 2 in the lower right hand corner distinguishes variables.
So $x_1$ is a different variable from $x_2$.
We might also call them simply $x$ and $y$.As for your equation, can you clarify it?
I read it as:
$$V_1=V_2-{u \over 1}-{uV_2 \over C_2}$$
But I suspect that is not what you intended.
What did you intend?Btw, as you can see I moved your post to a new thread, since it's a new topic.
 
  • #3
The problem is

V1=V2-u
-----
1-uV2
----
C2Solve for V2

How do I put symbols or equation on this page.
 
  • #4
Start by using parentheses. Every expression can be written in one line using parentheses. Remember the order of operations.
 
  • #5
jhanson58 said:
The problem is

V1=V2-u
-----
1-uV2
----
C2Solve for V2

How do I put symbols or equation on this page.

On our toolbar, you will see a button with the \(\displaystyle \sum\) character on it. Clicking this button will generate the MATH tags, between which you can put your $\LaTeX$ code. To see the code used by others, right click the expression, and from the pop-up menu choose Show Math As ► Tex Commands. You can then copy/past the code for your own use/modification.

There is a small learning curve to get familiar with the characters and commands, but once you get some practice it becomes second nature.
 
  • #6
jhanson58 said:
The problem is

V1=V2-u
-----
1-uV2
----
C2Solve for V2

How do I put symbols or equation on this page.

Is it like this?
$$V_1 = \frac {V_2 - u} {1 - \frac{uV_2}{C_2}}$$

Note that when you click Reply With Quote, you can see how I typed the formula and you can easily copy+paste it.
 
  • #7
I do not understand how to put the problem in correctly.when I right click on it. I do not see any symbols to help me.
 
  • #8
jhanson58 said:
I do not understand how to put the problem in correctly. when I right click on it.
Well, you should right-click a mathematical expression (and then select "Show Math As ► Tex Commands") in another post, like the following expression from post #6:
\[
V_1 = \frac {V_2 - u} {1 - \frac{uV_2}{C_2}}
\]
You may need to turn Javascript on in your browser. If this does not work, use other suggestions above.
 
Last edited:
  • #9
It looks to be like a variant on the velocity addition formula from SR:
[tex]\large v_1 = \frac {v_2 - u} {1 - \frac{uv_2}{c^2}}[/tex]

-Dan
 
  • #10
topsquark said:
It looks to be like a variant on the velocity addition formula from SR:
[tex]\large v_1 = \frac {v_2 - u} {1 - \frac{uv_2}{c^2}}[/tex]

-Dan

Nice one! ;)

Then, to solve $v_2$ from it, we can observe that in SR from the perspective of the other observer, the velocities are added instead of subtracted. Therefore:
$$v_2 = \frac {v_1 + u} {1 + \frac{uv_1}{c^2}}$$
 
  • #11
i need help! it says 0.999999... is 1! how can That be?
 
  • #12
Granny said:
i need help! it says 0.999999... is 1! how can That be?

Where does "it" say that?
 

FAQ: Solve V1=(V2-u)/(1-uV2/C2) for V2

How do I solve V1=(V2-u)/(1-uV2/C2) for V2?

To solve this equation, you can use algebraic manipulation to isolate V2 on one side of the equation. First, distribute the u to the numerator and denominator, giving you V1 = (V2u-u^2)/(1-u^2V2/C2). Next, multiply both sides by (1-u^2V2/C2), giving you V1(1-u^2V2/C2) = V2u-u^2. Then, distribute V1 and rearrange the terms to get V1-u^2 = V2(u-u^2V1/C2). Finally, divide both sides by (u-u^2V1/C2) to get the final answer, V2 = (V1-u^2)/(u-u^2V1/C2).

Can I simplify the equation V1=(V2-u)/(1-uV2/C2) for V2?

Yes, you can simplify the equation by factoring out V2 in the numerator, giving you V1 = V2(1-u)/(1-uV2/C2). Then, you can cancel out the (1-u) terms, giving you V1 = V2/C2. This simplified equation can be used to solve for V2.

How do I use this equation to solve for a specific variable?

To solve for a specific variable, you can use the same algebraic manipulation steps as mentioned in the first question. Just make sure to isolate the variable you want to solve for on one side of the equation, and rearrange the terms accordingly.

Can this equation be used for any type of problem?

This equation can be used for problems involving electrical circuits and Ohm's law, where V1 represents the voltage drop across a resistor, V2 represents the input voltage, u represents the resistance of the resistor, and C represents the capacitance of the circuit.

Are there any limitations to using this equation?

Yes, this equation assumes that the input voltage (V2) and resistance (u) are known values, and that there is only one resistor in the circuit. It also does not take into account any other factors that may affect the voltage drop, such as external power sources or other components in the circuit.

Similar threads

Replies
19
Views
2K
Replies
16
Views
2K
Replies
14
Views
531
Replies
2
Views
3K
Back
Top