- #1
Drain Brain
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I just want an alternative solution(preferably easier approach) to this problem
"A" can finish a job two hours longer than "B". After working for 1 hour, "B" joins him and they complete the job in 3 more hours. How long would it take "A" and "B" to finish a similar job if each worked alone?
my solution,
Let $B+2=$ A's required time to finish the job alone
$B=$ B's required time to finish the job alone
$\frac{1}{B+2}+3\left(\frac{1}{B+2}+\frac{1}{B}\right)=1$
solving for B I have
$B=6$hours
$A=8$hours
Regards!:)
"A" can finish a job two hours longer than "B". After working for 1 hour, "B" joins him and they complete the job in 3 more hours. How long would it take "A" and "B" to finish a similar job if each worked alone?
my solution,
Let $B+2=$ A's required time to finish the job alone
$B=$ B's required time to finish the job alone
$\frac{1}{B+2}+3\left(\frac{1}{B+2}+\frac{1}{B}\right)=1$
solving for B I have
$B=6$hours
$A=8$hours
Regards!:)