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Cuisine123
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Homework Statement
Solve for x. x is greater than or equal to 0 and x is less than or equal to 2pi.
(4/3)sinxcosx-sin22x=0
If there is a better way to approach this question than the way I did it below, please post it.
Thanks.
Homework Equations
N/A
The Attempt at a Solution
(4/3)sinxcosx-sin22x=0
2(2sinxcosx)-3sin22x=0
2(sin2x)-3sin22x=0
2sin2x-3sin22x=0
sin2x(2-3sinx)=0 <------I know this is incorrect. How do I factor the previous line correctly?
To solve the first part:
sin2x=0
2x=sin-1(0)=0,pi,2pi,3pi,4pi
therefore x=0, pi/2, pi, 3pi/2, 2pi
I know there are other solutions for x. Please help!
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