Solving 16•4^{-x}=4^x-6 Equation

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In summary, the conversation discusses a problem with solving the equation 16•4^{-x}=4^x-6 and suggests a solution involving substituting a variable and using logarithms. The person asking for help was able to solve the equation successfully.
  • #1
Petrus
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Hello MHB,
I am stuck on this equation and don't know what to do, If i take ln it does not work, any advice?
\(\displaystyle 16•4^{-x}=4^x-6\)

Regards,
\(\displaystyle |\pi\rangle\)
 
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  • #2
Try multiplying both sides by $4^x$. You get:
$$16 = (4^x)^2 - 6 \cdot 4^x$$
Now substitute $u = 4^x$. What do you see? :)
 
  • #3
Petrus said:
Hello MHB,
I am stuck on this equation and don't know what to do, If i take ln it does not work, any advice?
\(\displaystyle 16•4^{-x}=4^x-6\)

Regards,
\(\displaystyle |\pi\rangle\)

Set $4^{x}=y$, then solve for y and finally find $x = \frac{\ln y}{\ln 4}$ ...

Kind regards

$\chi$ $\sigma$
 
  • #4
Hello,
Thanks for the fast respond and help from you both!:) i succed to solve it with correct answer!:)
Regards,
\(\displaystyle |\pi\rangle\)
 
  • #5


Hello |\pi\rangle,

To solve this equation, we can use the properties of logarithms to rewrite it in a more manageable form. First, let's divide both sides by 4^x to get:

16•4^{-x}/4^x = (4^x-6)/4^x

Next, we can simplify the left side using the power rule of logarithms:

16•(4^x)^{-1} = (4^x-6)/4^x

Now, let's use the fact that (a^b)^c = a^{bc} to rewrite the left side as:

16•(4^{x\cdot -1}) = (4^x-6)/4^x

Using the fact that a^{-1} = 1/a, we can simplify the left side to get:

16•(1/4^x) = (4^x-6)/4^x

Now, we can use the fact that (a/b)^c = a^c/b^c to rewrite the left side as:

16/4^x = (4^x-6)/4^x

Finally, we can simplify the right side by dividing both the numerator and denominator by 4^x to get:

16/4^x = (4^x/4^x)-(6/4^x)

Using the fact that a^0 = 1, we can simplify the left side to get:

16/4^x = 1-6/4^x

Now, we have a simpler equation to solve:

16/4^x = 1-6/4^x

To solve for x, we can multiply both sides by 4^x to get:

16 = 4^x - 6

Adding 6 to both sides, we get:

22 = 4^x

Taking the logarithm of both sides, we get:

ln(22) = ln(4^x)

Using the fact that ln(a^b) = b•ln(a), we can rewrite the right side as:

ln(22) = x•ln(4)

Finally, we can solve for x by dividing both sides by ln(4):

x = ln(22)/ln(4)

Using a calculator, we can approximate this value to be around 1.415. Therefore, the solution to the equation is x = 1.
 

FAQ: Solving 16•4^{-x}=4^x-6 Equation

1. How do I solve 16•4-x=4x-6?

To solve this equation, you need to use logarithms. First, rewrite the equation in terms of a single base. In this case, you can use 4 as the base. So, 16•4-x can be rewritten as 42•4-x = 4x-6. This becomes 42-x = 4x-6. Now, take the logarithm of both sides (with base 4) to get 2-x = x-6. Solve for x to get the solution.

2. Can I use a different base for the logarithm?

Yes, you can use any base for the logarithm, as long as it is the same for both sides of the equation. However, using the same base as the one in the original equation simplifies the process.

3. How do I know which logarithm function to use?

In this case, you can use either the common logarithm (log) or the natural logarithm (ln). Both will give you the correct solution. However, if the base of the logarithm is not specified, it is usually assumed to be 10 (common logarithm) or e (natural logarithm).

4. Are there any restrictions on the values of x in this equation?

Yes, since you cannot take the logarithm of a negative number, the value of x must be such that both 42-x and 4x-6 are positive. In this case, x can take any value greater than or equal to 2.

5. Can I use a calculator to solve this equation?

Yes, you can use a calculator to solve this equation. Make sure to use the appropriate logarithm function and check for any restrictions on the values of x.

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