Solving 1D Motion Question with x>0, v<0, a>0

In summary, an example of a motion where x>0, v<0, a>0 at a particular instant is a car or ball moving with the position given by x(t)=A+Be^{-\gamma t}, where A>B and \gamma>0 are positive constants. Another example could be x(t) = 3t^2 -20t+100 at t=2, where the position is positive, the velocity is negative, and the acceleration is positive. Calculus can be used to find the values of x, v, and a at a specific time.
  • #1
mttal24
1
0

Homework Statement


Give example of a motion where x>0, v<0, a>0 at a particular instant.
x-->Position
v-->Velocity
a-->Acceleration


Homework Equations


I thought I had to give an example such as a car, ball etc.
But the answer says:
x(t) ie; position for time t; given by
x(t)=A+Be[itex]^{-\gamma t}[/itex]
where A>B, [itex]\gamma[/itex]>0 are chosen +ve constants.

The Attempt at a Solution


I don't know how to do it. Please help.
 
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  • #2
the given example wasnt the only solution

another example would be
x(t) = 3t^2 -20t+100 at t=2

for your example use calculus, for at t=1, x>0 as u can check
differentiate dx/dt = -γBe^(-γt), which is less than zero at t=1
differentiating again gives a=(γ^2)(B)(e^-yt) which is positive at t=1
 

FAQ: Solving 1D Motion Question with x>0, v<0, a>0

1. How do you solve a 1D motion question with x>0, v<0, a>0?

To solve a 1D motion question with these conditions, you can use the equation x = x0 + v0t + 1/2at^2. Plug in the given values for x0, v0, and a, then solve for t. Once you have the value of t, you can plug it back into the original equation to find the position at that time.

2. What does x>0, v<0, a>0 mean in a 1D motion problem?

In a 1D motion problem, x>0 means that the object's position is increasing, v<0 means that the object is moving in the negative direction, and a>0 means that the object is accelerating in the positive direction.

3. Can you use other equations to solve a 1D motion problem with x>0, v<0, a>0?

Yes, there are other equations that can be used to solve 1D motion problems, such as v = v0 + at and v^2 = v0^2 + 2a(x-x0). However, the equation x = x0 + v0t + 1/2at^2 is the most commonly used equation for these types of problems.

4. What units should be used for x, v, and a in a 1D motion problem with x>0, v<0, a>0?

The units for x should be in meters (m), v should be in meters per second (m/s), and a should be in meters per second squared (m/s^2). It is important to use consistent units throughout the problem to ensure accurate calculations.

5. Can you have negative values for x, v, or a in a 1D motion problem with x>0, v<0, a>0?

Yes, you can have negative values for x, v, or a in a 1D motion problem with these conditions. This indicates that the object is moving in the negative direction or decelerating. However, when plugging in values to the equation, make sure to use the correct signs for each variable.

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