Solving a complex numbered cubic equation

In summary: Six solutions is just a way of saying that there are six ways to write z = 1 in terms of the other terms in the equation.
  • #1
PcumP_Ravenclaw
106
4

Homework Statement


Solve the equation ## z^3 − z^2 + z − 1 = 0 ## first by inspection, and then by the
method described above. where Z is a complex number. (Alan F. Beardon, Algebra and Geometry)

The method described above is shown in the attachment.

Homework Equations


The method is shown in the attachment.

The Attempt at a Solution



Solve by inspection means to draw the graph of this equation and check where it intersects the x axis??
Shown in the attachment. the solution is 1 if i am not wrong

My algebraic solution is different. why? My attempt is also in the attachement.

Can you please also explain why there are six solutions for ## z ## when #z^3# has two solutions because of quadratic equation. cube root of any number has only one solutions which is the number itself. e.g. ## \sqrt[3]{-1} = -1*-1*-1 or \sqrt[3]{1} = 1*1*1## so cube root only gives one solution then what do they mean by six solutions??


danke...
 

Attachments

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  • #2
By inspection means just that: look at the terms of the equation and substitute some guesses which can be evaluated using mental arithmetic.

For the equation in the OP, looking at how the signs of the terms alternate, guessing that z = 1 is a solution is a solid hunch, since the magnitudes of z, z2, and z3 are all 1.
 
  • Like
Likes ComplexVar89
  • #3
"By inspection" often means just trying simple numbers. What do you get if you put z= 1 into the equation?
 
  • #4
Or you could look at the fist two terms, then look at the second two terms and notice these paddies have, er, a something in common. ;)
 
Last edited:
  • #5
PcumP_Ravenclaw said:
Can you please also explain why there are six solutions for ## z ##
It does not say there are six solutions for z. It says there are six solutions for ##\zeta##, but pairs of these produce the same value for z.
 

FAQ: Solving a complex numbered cubic equation

How do you solve a complex numbered cubic equation?

To solve a complex numbered cubic equation, you can use the cubic formula or factorization method. The cubic formula involves plugging in the coefficients of the equation into a formula, while factorization involves factoring the equation into simpler expressions.

What is the cubic formula and how does it work?

The cubic formula is a mathematical formula used to solve cubic equations of the form ax^3 + bx^2 + cx + d = 0. It involves using the coefficients of the equation to plug into the formula, and then simplifying the resulting complex numbers to find the solutions.

Is it possible to have multiple solutions to a complex numbered cubic equation?

Yes, a complex numbered cubic equation can have up to three solutions, including real and complex solutions. The number of solutions depends on the coefficients and the nature of the equation.

Can a complex numbered cubic equation have no solutions?

Yes, it is possible for a complex numbered cubic equation to have no solutions. This occurs when the equation cannot be factored and the resulting complex numbers from the cubic formula are not valid solutions.

Are there any special cases when solving a complex numbered cubic equation?

Yes, there are a few special cases when solving a complex numbered cubic equation. These include when the equation has all real coefficients, when the equation has a repeated root, or when the equation is in the form of a sum or difference of cubes.

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