- #1
MidgetDwarf
- 1,525
- 674
Solve the given differential equation by separation of variables.
(dy/dx)= (xy+3x-y-3)/(xy-2x+4y-8)
First, I noticed when i divided both sides by the left hand side and multiplied both sides by dx, nothing canceled or seemed to work.
I got to thinking.
on the right hand side I preformed long division.
i divided xy+3x-y-3 by xy-2x+4y-8.
I get 1 + (5x-5y+5)/(xy-2x+4y-8)
(dy/dx)= 1 + (5x-5y+5)/(xy-2x+4y-8)
I am stuck here. Any help is welcomed and appreciated.
(dy/dx)= (xy+3x-y-3)/(xy-2x+4y-8)
First, I noticed when i divided both sides by the left hand side and multiplied both sides by dx, nothing canceled or seemed to work.
I got to thinking.
on the right hand side I preformed long division.
i divided xy+3x-y-3 by xy-2x+4y-8.
I get 1 + (5x-5y+5)/(xy-2x+4y-8)
(dy/dx)= 1 + (5x-5y+5)/(xy-2x+4y-8)
I am stuck here. Any help is welcomed and appreciated.