- #1
asdf1
- 734
- 0
for the following question:
y`=1/(6e^y-2x)
my problem:
dx-(6e^y-2x)dy=0
so (1/F)(dF/dx)=2
=>F=e^2x
so e^2x-(e^2x)(6e^y-2x)dy=0
so (integration)(d^2x)dx=(1/2)e^2x +h(y)
=>h(y)= -6e^(2x+y)+xye^2x+c
so (1/2)e^2x-6e^(2x+y)+xye^2x+c-0
however the correct answer should be
y=ce^(-2y)+2e^y
does anybody know where my calculations went wrong?
y`=1/(6e^y-2x)
my problem:
dx-(6e^y-2x)dy=0
so (1/F)(dF/dx)=2
=>F=e^2x
so e^2x-(e^2x)(6e^y-2x)dy=0
so (integration)(d^2x)dx=(1/2)e^2x +h(y)
=>h(y)= -6e^(2x+y)+xye^2x+c
so (1/2)e^2x-6e^(2x+y)+xye^2x+c-0
however the correct answer should be
y=ce^(-2y)+2e^y
does anybody know where my calculations went wrong?