Solving a first order differentiation equation

  • #1
Pouyan_1989
1
0
Homework Statement
I got dizzy with strange solutions
Relevant Equations
y'(t) = k(M-y)
If we have this D.E:

from Latex :
lagrida_latex_editor.png


if I try to solve it in this way:

lagrida_latex_editor(1).png


My solution is :

lagrida_latex_editor(2).png


Which is not correct

Another attempt :

lagrida_latex_editor(3).png


that gives me :

lagrida_latex_editor(4).png




What is wrong ?

I know I should write:

lagrida_latex_editor(5).png


But why my integrations are wrong?
 
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  • #2
Because you have not done the integration correctly. If you do the integration correctly you will obtain the correct result.
 
  • #3
You can do it!

Your second answer is very close. Try to show your work this time, so you can find where you might have made a small mistake in the ##e## term.

This isn't that important, but ##A## is an undetermined constant, so you'd write ##A## instead of ##-A## to simplify the answer as much as possible.
 
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Likes SammyS
  • #4
@Pouyan_1989 your both answers are incorrect. To find where you are wrong it will be very useful if you show your work in more details.
 

FAQ: Solving a first order differentiation equation

What is a first order differential equation?

A first order differential equation is an equation that involves a function and its first derivative. It can generally be expressed in the form dy/dx = f(x, y), where y is the dependent variable, x is the independent variable, and f(x, y) is a given function of both x and y.

How do I solve a first order linear differential equation?

To solve a first order linear differential equation, you can use an integrating factor. The standard form is dy/dx + P(x)y = Q(x). First, calculate the integrating factor, μ(x) = e^(∫P(x)dx). Multiply the entire equation by μ(x) and then integrate both sides to find the general solution.

What is the difference between separable and non-separable differential equations?

A separable differential equation can be expressed in the form g(y)dy = h(x)dx, allowing you to separate the variables y and x. Non-separable equations cannot be rearranged in this way, and typically require different methods, such as using an integrating factor or specific techniques for exact equations.

What are initial value problems in the context of first order differential equations?

An initial value problem (IVP) involves a first order differential equation along with an initial condition, which specifies the value of the dependent variable at a particular point. The solution to the IVP must satisfy both the differential equation and the initial condition, allowing for a unique solution to be determined.

How can I verify my solution to a first order differential equation?

You can verify your solution by substituting it back into the original differential equation. If the left-hand side of the equation equals the right-hand side after substitution, then your solution is correct. Additionally, check that any initial conditions are satisfied if it's an initial value problem.

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