- #1
Flaming Toilet
Here's the question: A pair of fuzzy dice is hanging by a string from your rearview mirror. While you are acclerating from a stoplight to 20.0 m/s (in 5.0 sec.), what angle theta does the string make with the vertical?
Ok, I drew a force diagram with F (tension; upward direction)on the string and mg (weight) going down. Then, I found acceleration using the Vf-Vi divided by time : a=(Vf-Vi)/t
a=(20.0 m/s - 0 m/s)/5.0 s
a= 4.0 m/s squared
However, I have no idea what to do next. Can anyone give a hint(s) on what to do next?
Ok, I drew a force diagram with F (tension; upward direction)on the string and mg (weight) going down. Then, I found acceleration using the Vf-Vi divided by time : a=(Vf-Vi)/t
a=(20.0 m/s - 0 m/s)/5.0 s
a= 4.0 m/s squared
However, I have no idea what to do next. Can anyone give a hint(s) on what to do next?