- #1
pumaking94
- 5
- 0
I used to think I was master of any high school math course until I came across this log equation in a calculus textbook.
[itex]
\log_{2}x + \log_{5}(2x+1) = \ln x
[/itex]
I use the change of base to convert everything to one base and then I get down to:
[itex]
(2x+1)^{\ln2} = x^{\ln2\ln5 - \ln5}
[/itex]
I have no idea how to solve that. I found a website where they use graphing and later say that the algebraic solution is too difficult for beginner students. So what is the algebraic solution?
PS Sorry for posting in "General Math" but this isn't really a homework question...
[itex]
\log_{2}x + \log_{5}(2x+1) = \ln x
[/itex]
I use the change of base to convert everything to one base and then I get down to:
[itex]
(2x+1)^{\ln2} = x^{\ln2\ln5 - \ln5}
[/itex]
I have no idea how to solve that. I found a website where they use graphing and later say that the algebraic solution is too difficult for beginner students. So what is the algebraic solution?
PS Sorry for posting in "General Math" but this isn't really a homework question...
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