- #1
Jess89
- 1
- 0
Hello, please can someone tell me how to decouple and solve this equation? It was on a problem sheet, but the solution jumped to the decoupled equation... =(
[tex]
\frac{dx}{dt} = 2x+y-t
[/tex]
[tex]
\frac{dy}{dt}=2x-y+t
[/tex]
I know that it can rewritten as
[tex]
\frac{d}{dt}\left[ \begin{array}{cccc} 2 & 1\\ 2& -1 \end{array} \right] \left[\begin{array}{cccc} x\\ y \end{array}\right] + \left[ \begin{array}{cccc} -t\\ t \end{array} \right]
[/tex]
And for that matrix :
[tex]
\left[ \begin{array}{cccc} 2 & 1\\ 2& -1 \end{array} \right]
[/tex]
the eigenvalues and eigenvectors can be worked out.
But I don't know how to decouple =(
Thank you !
[tex]
\frac{dx}{dt} = 2x+y-t
[/tex]
[tex]
\frac{dy}{dt}=2x-y+t
[/tex]
I know that it can rewritten as
[tex]
\frac{d}{dt}\left[ \begin{array}{cccc} 2 & 1\\ 2& -1 \end{array} \right] \left[\begin{array}{cccc} x\\ y \end{array}\right] + \left[ \begin{array}{cccc} -t\\ t \end{array} \right]
[/tex]
And for that matrix :
[tex]
\left[ \begin{array}{cccc} 2 & 1\\ 2& -1 \end{array} \right]
[/tex]
the eigenvalues and eigenvectors can be worked out.
But I don't know how to decouple =(
Thank you !
Last edited: