- #1
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I'm studying for a test and I got stuck here.
Let A be the matrix:
3..1
2..1
In each part find p(a).
a) p(x)=x-2
The answer is:
1..1
2..-1
The only way I can see this happen is that we take the numbers on the diagonal and pluck it in p(x).
So...
x-2=3-2=1
x-2=1-2=-1
Leaving the others alone, we get.
1..1
2..-1
The problem is, I know this is WRONG. This method does not work for b) and c), which are polynomials of higher degrees.
The inverse is:
1..-1
-2..3
I still can see a solution pattern.
I tried to relate to the chapter, but no luck.
Any help is appreciated.
Let A be the matrix:
3..1
2..1
In each part find p(a).
a) p(x)=x-2
The answer is:
1..1
2..-1
The only way I can see this happen is that we take the numbers on the diagonal and pluck it in p(x).
So...
x-2=3-2=1
x-2=1-2=-1
Leaving the others alone, we get.
1..1
2..-1
The problem is, I know this is WRONG. This method does not work for b) and c), which are polynomials of higher degrees.
The inverse is:
1..-1
-2..3
I still can see a solution pattern.
I tried to relate to the chapter, but no luck.
Any help is appreciated.