Solving a Puzzling Physics Problem: Average Retarding Force

[nukengr10]

This is a fairly simple problem which i believe i know the answer to but the answer doesn't agree with the book i got it from.

Theres a 750 gram cart traveling 4 m/s, 2 meters later its traveling at 3 m/s. Calculate the average retarding force assuming only air resistance.

Here what I did:

KE= (1/2)*m*v^2 so deltaKE=(.5)*(.750)*(4^2-3^2)= 2.625

The Work=f*d. Since the Change in Kinetic Energy equals the work done on the object i did:
2.625=f*2. Hence f=(2.625/2)=1.3125 N.

I think that's right but is there something i might be possibly missing?

 

[arunbg]

Looks good to me.

 

[CSON]

I think it is wanting you to calculate the average air resistance (disricbed in force) that it would take to slow a 750 gram object from 4 m/s to 3 m/s in 2 meters.

 

[rockerdoctor]

i tried it a slightly different way and got the same answer, only negative. i did
2aΔx=v²-u²

where u=inital velocity, v=final velocity,a=acceleration and x being displacement.
so using that i got

a= (v²-u²)/2Δx

Fnet=ma

Fnet= m ((v²-u²)/2Δx)

plug all the numbers in and you get -1.312N, negative because you are decelerating in the negative x direction.

the big thing is you must watch your sign. if you have air resistance slowing you its not going to be the same sign as your x direction and velocity. velocity implies direction as well as speed. you can make your velocity negative based on where you allocate your x and y-axis relative to your direction, but then your force would be positive. always watch the sign.

 

[rockerdoctor]

"negative because you are decelerating in the negative x direction."

sorry, that is worded poorly. it should say, becuase you are decelerating in the positive x direction, meaning you are accelerating in the negative direction.

 

[nukengr10]

Thanks everyone, it has been quite good to see that other people got the same answer as i did...im pretty sure the book just mistyped the answers or something

 

[Kurdt]

Thanks everyone, it has been quite good to see that other people got the same answer as i did...im pretty sure the book just mistyped the answers or something

if it's a recent book it may have a web page with errata on it. If you come across something like this in the future it may be worth looking there first. If its not on the list you could send in the error you've found to the publishers.

 

[HallsofIvy]

This is a fairly simple problem which i believe i know the answer to but the answer doesn't agree with the book i got it from.

Theres a 750 gram cart traveling 4 m/s, 2 meters later its traveling at 3 m/s. Calculate the average retarding force assuming only air resistance.

Here what I did:

KE= (1/2)*m*v^2 so deltaKE=(.5)*(.750)*(4^2-3^2)= 2.625

The Work=f*d. Since the Change in Kinetic Energy equals the work done on the object i did:
2.625=f*2. Hence f=(2.625/2)=1.3125 N.

I think that's right but is there something i might be possibly missing?

I wouldn't have done it that way. At a constant acceleration (i.e. "average" acceleration), a body's "average" speed is "(initial speed+ final speed)/2". Here, the initial speed was 4 m/s and final speed was 3 m/s so its average speed during those 2 meters is (4+3)/2= 7/2 m/s. At that speed, it took 2/(7/2)= 4/7 seconds to travel 2 meters so its speed dropped from 4 m/s to 3 m/s, a difference of -1 m/s, in 4/7 seconds: the (average) acceleration was (-1)/(4/7)= -7/4= -1.75 m/s². Since the mass is 750 g= .75 kg, the force is (.75)(-1.75)= -1.3125 N as you say.

 

[nukengr10]

Yeah i couldn't find the errata and it is a fairly new book.