- #1
s7b
- 26
- 0
Hi,
I'm having problems solving this equation;
y'' -2y' +3y =0 y(0)=-1 , y'(0)=(root 2) -1
I found the auxiliary equation r^2 -2r +3 = 0
and since b^2 -4ac is less than zero this the case where r1 and r2 are complex numbers.
This is as far as I get without getting stuck.
Please help me out if you know this.
Thanks :)
I'm having problems solving this equation;
y'' -2y' +3y =0 y(0)=-1 , y'(0)=(root 2) -1
I found the auxiliary equation r^2 -2r +3 = 0
and since b^2 -4ac is less than zero this the case where r1 and r2 are complex numbers.
This is as far as I get without getting stuck.
Please help me out if you know this.
Thanks :)