Solving a Spring-Ladle Problem: Work Rate at Equilibrium and Beyond

In summary, the conversation is about a ladle attached to a horizontal spring with a kinetic energy of 10 J at the equilibrium position. The question is asking for the rate at which the spring is doing work on the ladle, which is zero at equilibrium. For part b, the spring is compressed and the ladle is moving away from equilibrium, and the group is discussing how to find the velocity and potential energy to solve for the rate of work.
  • #1
HobieDude16
70
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I don't understand how to start part b. Could someone please point me in the right direction? Thank you!

A 0.29 kg ladle sliding on a horizontal frictionless surface is attached to one end of a horizontal spring (k = 435 N/m) whose other end is fixed. The ladle has a kinetic energy of 10 J as it passes through its equilibrium position (the point at which the spring force is zero).
(a) At what rate is the spring doing work on the ladle as the ladle passes through its equilibrium position?
0 W
(b) At what rate is the spring doing work on the ladle when the spring is compressed 0.10 m and the ladle is moving away from the equilibrium position?
W
 
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  • #2
I really don't see how you could do part (a) and then have no idea how to start part (b). HOw about showing us what you have done?
 
  • #3
what i did for part a was just pretty much assume, and get it right. i figured when the spring force is zero, spring work is zero at equillibrium? right? then i don't know how to start part b. that's what i HAVE done
 
  • #4
well, so far, 6 of us are stumped on this one... nobody even knows how to start it
 
  • #5
I agree with you about (a). Zero force means zero work.

I assume that what they mean by the rate at which the spring is doing work on the ladle is the amount of work done per second. That means you will have to figure out what the velocity of the ladle is. To find the velocity, you must find the kinetic energy T, which of course satisfies E=T+V, where E is the total energy (which is known) and V is the potential energy. You should be able to figure out what V is if you know what the force is.
 
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FAQ: Solving a Spring-Ladle Problem: Work Rate at Equilibrium and Beyond

What is a spring-ladle problem?

A spring-ladle problem is a physics problem that involves a spring and a ladle (a long-handled spoon used for serving soup or stew). The goal of the problem is to determine the work rate at equilibrium and beyond, meaning the energy required to keep the spring compressed and the ladle in a balanced position.

How do you solve a spring-ladle problem?

To solve a spring-ladle problem, you need to use the principles of physics such as Hooke's law, which states that the force required to extend or compress a spring is directly proportional to the distance it is stretched or compressed. You also need to take into account the weight of the ladle and the gravitational force acting on it. By balancing these forces, you can determine the work rate at equilibrium and beyond.

What is the work rate at equilibrium?

The work rate at equilibrium refers to the energy required to keep the spring compressed and the ladle in a balanced position. This means that the forces acting on the ladle are equal and opposite, resulting in a state of equilibrium. The work rate at equilibrium can be calculated by multiplying the force acting on the spring by the distance it is compressed.

Can the work rate at equilibrium change?

Yes, the work rate at equilibrium can change if any of the factors involved in the problem change. For example, if the weight of the ladle is increased or the distance the spring is compressed is changed, the work rate at equilibrium will also change. However, as long as the forces are balanced, the ladle will remain in a state of equilibrium.

What is the significance of solving a spring-ladle problem?

Solving a spring-ladle problem allows us to understand and apply the principles of physics in real-life situations. It also helps us to develop problem-solving skills and critical thinking. Additionally, understanding the work rate at equilibrium and beyond can be useful in fields such as engineering and design, where understanding the forces acting on objects is crucial.

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