Solving a Trigonometry Problem: Uncovering "h

In summary, the conversation is about a trigonometry problem where the length of the leg adjacent to a 60-degree angle needs to be determined. The equations for tangent, cosine, and sine are provided and the attempt at solving the problem is discussed. The conversation ends with encouragement to keep trying and solving the equations using algebra.
  • #1
ooovooos
2
0

Homework Statement


[PLAIN]http://img530.imageshack.us/img530/5062/dgsdgsdgs.jpg
what is h??

Homework Equations


tan x = sin x/ cos x
cos x = adj/hyp
sin x = opp/hyp


The Attempt at a Solution


uh I am not even really sure where to start. i haven't done trig in a really really long time. I am guessing you have to use trig. and i set the area under the dotted triangle as x so the entire bottom length would be 100 + X but I am not even sure how that helps.
 
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  • #2
Add one unknown - length of the leg adjacent to 60° angle. You have two unknowns - h and the leg. Can you express tangents of both angles using these unknowns (and known length 100)?
 
  • #3
^ no offense but the "clue" you gave was so small that I'm just back where I started...confused...didnt really push me in any particular direction. -_-
tan 30 = h / (100 + x) = sqrt 3 over 3
tan 60 = h / x = sqrt 3?
i don't see how that helps.
i tried solving for h using the one that equals tan 60..that turns out to be x times sqrt 3...i plugged that into the first equation...and that just seems way too complicated. I did this type of question two years ago in HS...i am so sure this question isn't supposed to be this complicated.
 
  • #4
ooovooos said:
i tried solving for h using the one that equals tan 60..that turns out to be x times sqrt 3...i plugged that into the first equation...and that just seems way too complicated. I did this type of question two years ago in HS...i am so sure this question isn't supposed to be this complicated.

Is this the equation you got?

[tex]\frac{x\sqrt{3}}{100 + x} = \frac{\sqrt{3}}{3}[/tex]

It requires a bit of algebra, but it's not bad.
 
  • #5
ooovooos said:
i tried solving for h using the one that equals tan 60..that turns out to be x times sqrt 3...i plugged that into the first equation...

You got to two equations in two unknowns, and you are solving them using correct approach. Just don't give up.
 

FAQ: Solving a Trigonometry Problem: Uncovering "h

What is "h" in a trigonometry problem?

"h" typically represents the length of the hypotenuse in a right triangle. It is the longest side and is directly opposite the right angle.

How can I solve for "h" in a trigonometry problem?

To solve for "h", you will need to use the Pythagorean Theorem, which states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the other two sides. You can also use trigonometric ratios, such as sine, cosine, and tangent, to solve for "h" depending on the given information.

What information do I need to solve for "h" in a trigonometry problem?

You will need at least one side length and one angle measurement in the right triangle to solve for "h". This can be provided in either degrees or radians. If you have both side lengths and an angle measurement, you can use the trigonometric ratios to solve for "h".

Why is it important to solve for "h" in a trigonometry problem?

Solving for "h" allows you to find the missing side length in a right triangle, which is crucial for many real-life applications, such as construction, navigation, and engineering. It also helps in understanding and visualizing the relationship between the sides and angles of a right triangle.

What are some common mistakes when solving for "h" in a trigonometry problem?

One common mistake is using the wrong trigonometric ratio for the given information. Another mistake is not converting between degrees and radians when necessary. It is also important to pay attention to the given information and use the correct formula or equation to solve for "h".

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