Solving an Equation in [-90,0]: Sec2A-3tanA-5=0

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In summary, the equation sec2A - 3tanA - 5=0, for A \in[-90,0] can be solved by rewriting sec^2A in terms of the tangent and then substituting and solving the resulting quadratic equation.
  • #1
DERRAN
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Homework Statement


Solve the Equation:

sec2A - 3tanA - 5=0, for A [tex]\in[/tex][-90,0]

Homework Equations





The Attempt at a Solution


[tex]\frac{1}{cos^{2}A}[/tex] - [tex]\frac{3sinA}{cosA}[/tex] -5 =0

[tex]\frac{1-3sinA.cosA}{cos^{2}A}[/tex] -5 = 0

?
Did I go wrong? If not I'm stuck. Please help. Thank you.
 
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  • #2
You didn't go wrong, but the form you wrote it in only makes it harder. I suggest you write the [itex]\sec^2 A[/itex] term in terms of the tangent. Do you know how?
 
Last edited:
  • #3
[tex]sec^2A=\frac{1}{cos^2A}=\frac{sin^2A+cos^2A}{cos^2A}=\frac{sin^2A}{cos^2A}+\frac{cos^2A}{cos^2A}=tan^2A+1[/tex]

Just substitute and solve the quadratic equation.

Regards.
 
  • #4
thanks
 

FAQ: Solving an Equation in [-90,0]: Sec2A-3tanA-5=0

How do I solve an equation in the given interval?

To solve an equation in a given interval, you will need to use the properties of the trigonometric functions and apply them to the given equation. In this case, you will need to use the double angle formula for secant and the identity for tangent.

What is the first step in solving this equation?

The first step in solving this equation is to rewrite it in terms of one variable, preferably either secant or tangent. In this case, we can rewrite the equation as sec²A - 3tanA - 5 = 0.

How do I use the double angle formula for secant in this equation?

The double angle formula for secant is sec²2x = 1 + tan²x. In this equation, we can replace sec²A with 1 + tan²A to simplify the equation.

Can I use a calculator to solve this equation?

Yes, you can use a calculator to solve this equation. However, you will need to use the inverse trigonometric functions to solve for the angle A. You can use the inverse secant and inverse tangent functions on your calculator to find the values of A.

Are there any restrictions on the values of A for this equation?

Yes, since we are solving in the interval [-90,0], the values of A must fall within this range. Additionally, the tangent function is undefined at ±90 degrees, so we must exclude these values from our solutions.

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