- #1
Axecutioner
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I need to find the equation of motion of a double pendulum, as shown here:
I've gotten as far as the two euler-lagrange differential equations, simplified to this:
K1[itex]\ddot{θ}[/itex]1 + K2[itex]\ddot{θ}[/itex]2cos(θ1 - θ2) + K3[itex]\dot{θ}[/itex]22sin(θ1 - θ2) + K4sin(θ1) = 0
K5[itex]\ddot{θ}[/itex]2 + K6[itex]\ddot{θ}[/itex]1cos(θ1 - θ2) + K7[itex]\dot{θ}[/itex]12sin(θ1 - θ2) + K8sin(θ2) = 0
Assuming initial conditions [itex]\ddot{θ}[/itex]1o, [itex]\dot{θ}[/itex]1o, θ1o, [itex]\ddot{θ}[/itex]2o, [itex]\dot{θ}[/itex]2o, θ2o
What would these equations of motion be?
θ1(t) =
θ2(t) =
I was told it could be done in MATLAB but I don't have the software or know how to use it yet so any help would be appreciated. Step-by-step solution would be even better. Thanks in advance.
I've gotten as far as the two euler-lagrange differential equations, simplified to this:
K1[itex]\ddot{θ}[/itex]1 + K2[itex]\ddot{θ}[/itex]2cos(θ1 - θ2) + K3[itex]\dot{θ}[/itex]22sin(θ1 - θ2) + K4sin(θ1) = 0
K5[itex]\ddot{θ}[/itex]2 + K6[itex]\ddot{θ}[/itex]1cos(θ1 - θ2) + K7[itex]\dot{θ}[/itex]12sin(θ1 - θ2) + K8sin(θ2) = 0
Assuming initial conditions [itex]\ddot{θ}[/itex]1o, [itex]\dot{θ}[/itex]1o, θ1o, [itex]\ddot{θ}[/itex]2o, [itex]\dot{θ}[/itex]2o, θ2o
What would these equations of motion be?
θ1(t) =
θ2(t) =
I was told it could be done in MATLAB but I don't have the software or know how to use it yet so any help would be appreciated. Step-by-step solution would be even better. Thanks in advance.