Solving Center of Mass Prob: Stick Length 0.25m, Mass 0.53kg

AI Thread Summary
The problem involves a stick of length 0.25 m and mass 0.53 kg thrown horizontally, with its center of mass rising vertically. At release, the speed of the end nearest to the thrower is zero, and the stick completes 33 revolutions before reaching its highest point. To solve for the time taken to reach this peak, one can relate the angular speed to the time and use the relationship between the center of mass speed and angular speed. The acceleration due to gravity is 9.8 m/s², which is crucial for calculating the motion. Understanding these relationships is key to finding the solution.
SsUeSbIaEs
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Can someone please help me with this problem, a hint, anything something?

A girl throws a stick with a length of 0:25 m
and a mass of 0.53 kg into the air in such a
way that the center of mass rises vertically.
At the moment it leaves her hand, the stick
is horizontal and the speed of the end of the
stick nearest to her is zero. When the center
of mass of the stick reaches its highest point,
the stick is horizontal, and it has made 33
complete revolutions. Assume that the stick's
cross sectional area and mass is uniform.
The acceleration of gravity is 9.8 m/s^2 (speed of stick end
is zero when it leaves her hand)
How long did it take for the center of mass
to reach its highest point? Answer in units of
s.
 
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Originally posted by SsUeSbIaEs
Can someone please help me with this problem, a hint, anything something?
Realize that you can express the angular speed ω of the stick in terms of the time it takes to get to the top, which is what you are trying to find. Also realize that at the moment the stick is released, the speed of the center of mass is related to the angular speed of the stick: V=ωR. Then apply what you (I hope) know about accelerated motion.
 
Thanks that helped a lot!
 
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