- #1
Rozenwyn
- 31
- 0
http://img209.imageshack.us/img209/8136/423ky7.jpg
I have trouble getting the correct answers.
I tried:
At node V1 [tex]\ i_1 + \frac{v_2-v_1}{5} = \frac{v_1}{20} \ \longrightarrow[/tex] Solve for [tex]i_1[/tex]
ok let's try.
[tex] i_1 + \frac{15-4}{5} = \frac{4}{20}[/tex]
[tex] i_1 = \frac{1}{5} - \frac{11}{5} [/tex]
[tex] i_1 = \frac{-10}{5} = -2A[/tex]
@Cornea: Indeed, the equations seem to be correct. *bangs head to the table.* Can't believe a sign error could waste 2 hrs of my life. Hmmm, need more sleep ... more sleep.
Then;
Ar node V2 [tex]\ \frac{v_2-v_1}{5} + \frac{v_2-v_3}{15} = i_2 \ \longrightarrow[/tex] Solve for [tex]i_2[/tex]
When I solve for [tex]i_1, \ i_2[/tex] I get wrong answers.
I have trouble getting the correct answers.
I tried:
At node V1 [tex]\ i_1 + \frac{v_2-v_1}{5} = \frac{v_1}{20} \ \longrightarrow[/tex] Solve for [tex]i_1[/tex]
ok let's try.
[tex] i_1 + \frac{15-4}{5} = \frac{4}{20}[/tex]
[tex] i_1 = \frac{1}{5} - \frac{11}{5} [/tex]
[tex] i_1 = \frac{-10}{5} = -2A[/tex]
@Cornea: Indeed, the equations seem to be correct. *bangs head to the table.* Can't believe a sign error could waste 2 hrs of my life. Hmmm, need more sleep ... more sleep.
Then;
Ar node V2 [tex]\ \frac{v_2-v_1}{5} + \frac{v_2-v_3}{15} = i_2 \ \longrightarrow[/tex] Solve for [tex]i_2[/tex]
When I solve for [tex]i_1, \ i_2[/tex] I get wrong answers.
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