- #1
Jason03
- 161
- 0
I was working on this circuit.
http://img404.imageshack.us/img404/3537/imptm6.jpg
The problem asks to find the current through the R2 branch...
Heres my approach and questions...
Start from the opposite end of the circuit...combine the 2 parallel resistors R2 and R3...the V2 goes to zero because of the superposition...
The only question I had was are R1 and XL in parallel?...if so I could combine the R2 and R3 total found with R1..using product sum rule...
Finally add XC to (XL)(R1)/(XL + R1)...to get the total impedence
than from there find the current...(current divider)
http://img404.imageshack.us/img404/3537/imptm6.jpg
The problem asks to find the current through the R2 branch...
Heres my approach and questions...
Start from the opposite end of the circuit...combine the 2 parallel resistors R2 and R3...the V2 goes to zero because of the superposition...
The only question I had was are R1 and XL in parallel?...if so I could combine the R2 and R3 total found with R1..using product sum rule...
Finally add XC to (XL)(R1)/(XL + R1)...to get the total impedence
than from there find the current...(current divider)
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