- #1
DryRun
Gold Member
- 838
- 4
Homework Statement
Given that the real and imaginary parts of the complex number [itex]z=x+iy[/itex] satisfy the equation [itex](2-i)x-(1+3i)y=7[/itex]. Find x and y.
The attempt at a solution
I know it's quite simple. Just equate the real and imaginary parts, but i checked and redid it again, but the answer still evades me!
[tex](2x-y-7) + i(-x-3y)=0
\\2x-y-7=x
\\x-y=7\, (1)
\\-x-3y=y
\\4y+x=0\, (2)
\\x=28/5
\\y=-7/5
[/tex]
I replaced in the original equation but i can't get 7 on the L.H.S.
The correct answers: x=3 and y=-1.
Given that the real and imaginary parts of the complex number [itex]z=x+iy[/itex] satisfy the equation [itex](2-i)x-(1+3i)y=7[/itex]. Find x and y.
The attempt at a solution
I know it's quite simple. Just equate the real and imaginary parts, but i checked and redid it again, but the answer still evades me!
[tex](2x-y-7) + i(-x-3y)=0
\\2x-y-7=x
\\x-y=7\, (1)
\\-x-3y=y
\\4y+x=0\, (2)
\\x=28/5
\\y=-7/5
[/tex]
I replaced in the original equation but i can't get 7 on the L.H.S.
The correct answers: x=3 and y=-1.