- #1
Kyoma
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Homework Statement
15 cm3 of 0.200 mol dm-3 sodium hydroxide solution was made up to 100 cm3 with 0.120 mol dm-3 sodium sulfate solution. Determine the molar concentration of sodium cations in the resultant mixture.
2. The attempt at a solution
Moles of sodium ions in sodium hydroxide = 0.200 x (15/1000) = 0.003 mol
Let volume of sodium sulfate be Vx.
(0.120Vx) x 2 + 0.003 = Total moles of sodium ions
After which, i find it hard to proceed. :(