- #1
HWGXX7
- 46
- 0
Hello,
I got into a very little and simple problem which I should understand. But I don't..
Look at this picture:
The mass naturally will move downwards from the hill. Oke, no problem. Analysing the external forces applied to this mass: gravity and friction.
Gravity, independent of time.
[tex]F_{g}=m.g[/tex]
Friction force, depents on the speed the mass is moving down.
[tex]F_{w}=k.\frac{dx}{dt}[/tex]
This I do understand.
Aply Newton second law: [tex]\sum F=m.a[/tex], this is a vectorial equation.
Means that the orientation of the forces is important, you also know this offcourse.
Now the tricky part I can't understand: I know de speed of the mass is getting smaller en smaller because de mass is slowing down because of friction.
Acceleration is defined as :[tex]a=\frac{dv}{dt}[/tex], in this case the derivative is negative.
So [tex]m.a[/tex] is also negative and must orient in the negative x direction...
I know I'am wrong but I can't find a decent reason in my logic for it..
gratefull for help
I got into a very little and simple problem which I should understand. But I don't..
Look at this picture:
The mass naturally will move downwards from the hill. Oke, no problem. Analysing the external forces applied to this mass: gravity and friction.
Gravity, independent of time.
[tex]F_{g}=m.g[/tex]
Friction force, depents on the speed the mass is moving down.
[tex]F_{w}=k.\frac{dx}{dt}[/tex]
This I do understand.
Aply Newton second law: [tex]\sum F=m.a[/tex], this is a vectorial equation.
Means that the orientation of the forces is important, you also know this offcourse.
Now the tricky part I can't understand: I know de speed of the mass is getting smaller en smaller because de mass is slowing down because of friction.
Acceleration is defined as :[tex]a=\frac{dv}{dt}[/tex], in this case the derivative is negative.
So [tex]m.a[/tex] is also negative and must orient in the negative x direction...
I know I'am wrong but I can't find a decent reason in my logic for it..
gratefull for help