- #1
pardesi
- 339
- 0
i was solving thsi problem
and attempted it in this manner
consider a length [tex]dx[/tex] of the rod at a distance [tex]x[/tex] from the pivot now
let [tex]\theta[/tex] be the required angle
[tex]dx\cos\theta = dm g[/tex]
[tex]dx\sin\theta = m\omega^{2}x\sin\theta[/tex]
dividing we get [tex]\tan\theta = \frac {\omega^{2}x\sin\theta}{g}[/tex] which is obviously false
and attempted it in this manner
consider a length [tex]dx[/tex] of the rod at a distance [tex]x[/tex] from the pivot now
let [tex]\theta[/tex] be the required angle
[tex]dx\cos\theta = dm g[/tex]
[tex]dx\sin\theta = m\omega^{2}x\sin\theta[/tex]
dividing we get [tex]\tan\theta = \frac {\omega^{2}x\sin\theta}{g}[/tex] which is obviously false