Solving Differential Operator with D for 4(x^2)(D^2)+12xD+3

In summary, the conversation discusses how to solve an equation with variable coefficients. It is suggested to treat the equation as a regular Euler-Cauchy equation and find a solution of the form y=x^m. Some participants also mention trying to factor the equation, but it is noted that this method does not work with variable coefficients.
  • #1
asdf1
734
0
for the following question:
[4(x^2)(D^2)+12xD+3)]y=0

my problem:
i only know how to solve this type of question if i change it back to its original form. however, if i want to solve it by just using D, how would i do that?
 
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  • #2
What do you mean its original form?

And what are you expected to do with this equation anyway?
 
  • #3
i mean that if i changed the D to y``
 
  • #4
OH! Well I guess just treat Dy as dy/dx and solve as you would.
 
  • #5
quasar987 said:
OH! Well I guess just treat Dy as dy/dx and solve as you would.

I looked at it early this morning and even briefly posted what I though was the factored form of the differential operators and even though it resulted in a correct answer, my factored version was incorrect because the differential operators are NOT commutative. Turns out equations with functions of x are not easily factored for this reason, something I'm not clear on. So I would just treat it as a regular Euler-Cauchy equation and look for a solution of the form:

[tex]y=x^{m}[/tex]

(unless someone can further comment about the factoring).:smile:
 
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  • #6
i had the same problem as you when i tried to factor it too~
 
  • #7
This ia a quadratic in D.Just find out D using the formula used for quadratic equations and then proceed
 
  • #8
Harmeet Singh said:
This ia a quadratic in D.Just find out D using the formula used for quadratic equations and then proceed
The whole point is that this is an equation with VARIABLE coefficients. That method doesn't work with variable coefficients.
 
  • #9
@@ why doesn't it work for variable coefficients?
 

FAQ: Solving Differential Operator with D for 4(x^2)(D^2)+12xD+3

What is a differential operator?

A differential operator is a mathematical operation that involves differentiation, typically denoted by the symbol D. In this context, D represents the derivative of a function.

How do you solve a differential operator?

To solve a differential operator, you need to apply the operator to the given function. In this case, the given function is 4(x^2)(D^2)+12xD+3. This means taking the second derivative of the function and multiplying it by 4, then adding the first derivative multiplied by 12, and finally adding 3.

What does the notation (D^2) mean in this context?

The notation (D^2) means that the operator, in this case D, is applied twice. This is known as the second derivative.

What is the purpose of using a differential operator?

Differential operators are used in mathematics to solve differential equations, which are equations that involve derivatives of a function. They help to find the general solution to these equations, which can then be used to solve specific problems.

Can you provide an example of how to solve a differential operator?

Yes, for example, if we have the function f(x) = x^2, we can apply the differential operator D to get the first derivative, which is D(x^2) = 2x. We can then apply the operator again to get the second derivative, which is D^2(x^2) = 2. So, in this case, the differential operator D^2 would give us the constant 2.

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