- #1
Schwartz
- 5
- 0
I need to solve a double integral and I have no idea what to change the variables to:
[tex] \iint_{R} \cos ( \frac{y-x}{y+x}) \ dA [/tex]
[tex] R=\{(x,y) \mid \ -x+1 \leq y \leq -x+2, 1 \leq x \leq 2 \}
[/tex]
I tried to set [itex] u=y-x [/itex] and [itex]v=y+x[/itex], but I still can't solve the resulting integral. I also tried setting [itex] v + u= \frac{y-x}{y+x} [/itex] and differentiating implicitly when finding the Jacobian, but the Jacobian turns out to be zero.
[tex] \iint_{R} \cos ( \frac{y-x}{y+x}) \ dA [/tex]
[tex] R=\{(x,y) \mid \ -x+1 \leq y \leq -x+2, 1 \leq x \leq 2 \}
[/tex]
I tried to set [itex] u=y-x [/itex] and [itex]v=y+x[/itex], but I still can't solve the resulting integral. I also tried setting [itex] v + u= \frac{y-x}{y+x} [/itex] and differentiating implicitly when finding the Jacobian, but the Jacobian turns out to be zero.
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