Solving Electron Deflection in a Parallel Plate Apparatus

In summary, an electron enters a parallel plate apparatus with a length of 10 cm and a width of 2.0 cm, moving horizontally at a speed of 8.0 x 10^7 m/s. The potential difference across the plates is 600V. Using the equation v = sqrt (2qv/m), we can calculate the vertical deflection of the electron from its original path and the velocity at which it leaves the parallel plate apparatus in both magnitude and direction. The electric field produced by the plates can be found by dividing the potential difference by the width of the plates. Neglecting gravity, we can find the acceleration of the electron by using the formula F=ma. The electron experiences an acceleration along the y
  • #1
lovemake1
149
1

Homework Statement



Question Reads:

An electron enters a parallel plate apparatus 10 cm long and 2.0 wide, moving horizontally at 8.0 10 ^7 m/s. if the potential difference across the plates is 600V, determine

a) the vertical deflection of the electron from its original path
b) the velocity with whih it leaves the parallel plate appratus, in both maginitude and direction

Homework Equations

,

v = sqrt ( 2qv / m )



The Attempt at a Solution



i have no clue where to start, but i guess this is like a projectile motion ? with gravity applied?
 
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  • #2
lovemake1 said:

The Attempt at a Solution



i have no clue where to start, but i guess this is like a projectile motion ? with gravity applied?

Yes it is like projectile motion, except not with gravity.

If the pd is 600 V and the plates are 2m wide, what is the electric field produced?

Also if the electric field is the force exerted per unit charge and F=ma, what is the acceleration?
 
  • #3
you can straight away neglect gravity. calculate & see yourself how small mg is in comparison to qE.

the elec field is perpendicular to the electron's initial velocity. say electron was initially moving along x & the field is along y.

now the filed accelerates the electron along y.
first, find out the time taken for the electron to leave the setup.
that is just length / vx. (vx = initial velocity. does not change)

so electron experiences an acceleration along y for this much time. so u can find vy.
 

FAQ: Solving Electron Deflection in a Parallel Plate Apparatus

1. What is an electron deflection apparatus?

An electron deflection apparatus is a scientific instrument used to study the behavior of electrons in electric fields. It typically consists of two parallel metal plates with an electric potential difference between them, which causes the electrons to move and deflect in a predictable manner.

2. How does an electron deflection apparatus work?

The electron deflection apparatus works by applying an electric field between two parallel plates. This electric field causes the electrons to move and deflect, with the degree of deflection depending on the strength of the electric field and the mass and charge of the electrons.

3. What are the applications of an electron deflection apparatus?

An electron deflection apparatus is commonly used in research and educational settings to study the properties of electrons and their behavior in electric fields. It can also be used in the development of electronic devices and technologies.

4. What factors affect electron deflection in a parallel plate apparatus?

The degree of electron deflection in a parallel plate apparatus is affected by the strength of the electric field, the distance between the plates, and the mass and charge of the electrons. Other factors such as temperature and external magnetic fields may also have an impact.

5. How can I calculate the degree of deflection in an electron deflection apparatus?

The degree of electron deflection in a parallel plate apparatus can be calculated using the formula F = Eq, where F is the force on the electron, E is the electric field strength, and q is the charge of the electron. By measuring the electric field and the distance between the plates, the degree of deflection can be determined.

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