- #1
Jules18
- 102
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Hey guys, I've tried this question a couple different ways. Please help!
Calculate the concentration of the acetate ion (M) in a solution prepared by dissolving 1.00×10-3 mol of HCl(g) in 1.00 L of 1.90 M aqueous acetic acid. Ka = 1.7E-5
And at that point I'm not sure what to do.
... CH3COOH --> CH3COO- + H+
initial: 1.90 M 0 0
change: - x +x +x
equlbm: ~1.9 x x
I did some calculations and found that x = 5.68E-3 . I that didn't take the HCl into consideration, though - I really have no idea what to do with that. i
Homework Statement
Calculate the concentration of the acetate ion (M) in a solution prepared by dissolving 1.00×10-3 mol of HCl(g) in 1.00 L of 1.90 M aqueous acetic acid. Ka = 1.7E-5
And at that point I'm not sure what to do.
Homework Equations
... CH3COOH --> CH3COO- + H+
initial: 1.90 M 0 0
change: - x +x +x
equlbm: ~1.9 x x
The Attempt at a Solution
I did some calculations and found that x = 5.68E-3 . I that didn't take the HCl into consideration, though - I really have no idea what to do with that. i