Solving f(x) Substitution: 1/x +1-(1/x)/h

In summary, the problem is to simplify the expression f(h+1)-f(h)/h, given that f(x)=1/x. After substituting f(x) with 1/x, the correct solution is found to be (1/x+1 -1/x)/h. The final simplified expression is 1/hx^2+hx.
  • #1
yoleven
78
1

Homework Statement


f(h+1)-f(h)/h. If f(x)=1/x, simplify.


Homework Equations





The Attempt at a Solution


1/x+1-(1/x)/h

is the answer 1/h? I am not sure if i substituted this correctly or if I solved this right.
I put 1/x in everywhere there was a f(h).
 
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  • #2
If f(x)=1/x, then f(h+1)=1/(h+1), f(5)=1/5. Etc. x is only a dummy variable.
 
  • #3
Incorrect.

f(h+1)=1/(h+1)

f(h)=1/h

[f(h+1)-f(h)]/h

[1/(h+1)-1/h]/h

Continue.
 
  • #4
so it should have been (1/x+1 -1/x)/h
dealing with the numerator first, I bring the terms to a common denominator..
(x-x+1/x^2+x)/h.
i multiply the numerator by 1/h and get..
1/hx^2+hx
is that right?
 
  • #5
You aren't listening. There are NO x's in (f(h+1)-f(h))/h. Reread the previous posts. By the way, are you sure the problem isn't (f(h+1)-f(1))/h??
 
Last edited:
  • #6
Okay, I can see that now. Thanks.
 

FAQ: Solving f(x) Substitution: 1/x +1-(1/x)/h

How do I solve for x in the equation f(x) = 1/x + 1 - (1/x)/h?

To solve for x in this equation, you will need to use substitution. First, let f(x) = y, then substitute y into the equation: y = 1/x + 1 - (1/x)/h. Simplify the equation to solve for x.

What is the role of h in this equation?

H is a constant value that is used in the equation to represent a specific number. It is important to include h in the equation when solving for x, as it will affect the final answer.

Can I solve this equation without using substitution?

No, substitution is necessary in this equation in order to solve for x. It allows you to simplify the equation and isolate x on one side.

How can I check if my solution for x is correct?

To check your solution for x, you can plug the value back into the original equation and see if it satisfies the equation. If it does, then your solution is correct.

Are there any restrictions on the values of x and h in this equation?

Yes, since the equation involves a fraction, x and h cannot equal zero. Additionally, h cannot equal 1 as it would result in division by zero. Other than that, there are no restrictions on the values of x and h.

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