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Classic49
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1. I am trying to help my grandson with his homework and I have to determine the flow of a fluid in a pipe. I am told that mass flow rate is 4Kg/s; density p is 1012Kg/m3; Diameters D1 = 300mm, D2 = 400mm; Pressure P1 = 700Pa, P2 = 600Pa; Heights y1=0mm, y2=100mm
2. I have applied Bernoulli's Equation, Continuity Equation and Mass Flow Rate but get different results so am not sure where I am going wrong.
3. Putting values into the Bernoulli equation, we have:
700 + (1012 x 9.81 x 0) + (½ x 1012 x V12) = 600 + (1012 x 9.81 x 0.1) + (½ x 1012 x V22)
This simplifies to:
700 + 0 + (506 x V12) = 600 + 992.772 +(506 x V22), or
506 x V12 = 600 + 992.772 - 700 +(506 x V22) = 892.772 +(506 x V22)I need to determine V1 and V2 so I tried using the Continuity equation to establish a relationship between the two. From the gives diameters, Areas are A1 = 0.07065 m2 , A2 = 0.1256 m2
Therefore V1 = (V2 x A2)/A1 =( V2 x 0.1256)/0.07065 = 1.78 x V2
Putting the value of V1 into the Bernoulli equation above, I get
506 x (1.78 x V2)2 = 892.772 +(506 x V22)
This gives me V2 = 0.902 m/s
From the Continuity Equation, V1 = 1.78 x V2 = 1.6 m/s
4. The piece of information I have not used is the Mass Flow Rate. If I use the information in the equation
Mass Flow Rate = Density (p) x Area (A1) x Velocity (V1), I get V1 = 4/(1012 x 0.07065) = 0.0559 and
V2 = 4/(1012 x 0.1256) = 0.0315 which are widely different from the values calculated above.
5. I would be grateful for some guidance as to where I am going wrong.
2. I have applied Bernoulli's Equation, Continuity Equation and Mass Flow Rate but get different results so am not sure where I am going wrong.
3. Putting values into the Bernoulli equation, we have:
700 + (1012 x 9.81 x 0) + (½ x 1012 x V12) = 600 + (1012 x 9.81 x 0.1) + (½ x 1012 x V22)
This simplifies to:
700 + 0 + (506 x V12) = 600 + 992.772 +(506 x V22), or
506 x V12 = 600 + 992.772 - 700 +(506 x V22) = 892.772 +(506 x V22)I need to determine V1 and V2 so I tried using the Continuity equation to establish a relationship between the two. From the gives diameters, Areas are A1 = 0.07065 m2 , A2 = 0.1256 m2
Therefore V1 = (V2 x A2)/A1 =( V2 x 0.1256)/0.07065 = 1.78 x V2
Putting the value of V1 into the Bernoulli equation above, I get
506 x (1.78 x V2)2 = 892.772 +(506 x V22)
This gives me V2 = 0.902 m/s
From the Continuity Equation, V1 = 1.78 x V2 = 1.6 m/s
4. The piece of information I have not used is the Mass Flow Rate. If I use the information in the equation
Mass Flow Rate = Density (p) x Area (A1) x Velocity (V1), I get V1 = 4/(1012 x 0.07065) = 0.0559 and
V2 = 4/(1012 x 0.1256) = 0.0315 which are widely different from the values calculated above.
5. I would be grateful for some guidance as to where I am going wrong.
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