Solving Fluid Statics Problem: Accounting for Atmospheric Pressure

  • #1
member 731016
Hi!

For this fluid statics problem,
1669440301598.png


One of the answers is:
1669440335829.png

However, why did they assume the pressure at the top was zero? I thought the pressure at the top would be 1 atm?

So tried to take atmospheric pressure into account putting 1 atm at the top,
p02BmFMz8bsEq6v6b6YrLD4C2XVxcmjDIvK6DND5Ijn6d5RGSw.png

Do you please know how to get P_0A/2 so that the P_0A/2 terms can cancel to get their hydrostatic force? I assume that the atmospheric pressure is the same at the top and bottom since the height of the dam is negligible to the scale of the atmosphere.

Many thanks!
 
Physics news on Phys.org
  • #2
Callumnc1 said:
However, why did they assume the pressure at the top was zero? I thought the pressure at the top would be 1 atm?
That one atmosphere is present above the water, through the water column, and also against the dry face of the dam wall. Those two atmospheric forces on the two sides of the dam wall oppose each other, and so can be cancelled.
 
  • #3
Moderator's note: Thread moved to introductory physics homework forum.
 
  • #4
How did you calculate Pavg?
 
  • Like
Likes Orodruin
  • #5
Baluncore said:
That one atmosphere is present above the water, through the water column, and also against the dry face of the dam wall. Those two atmospheric forces on the two sides of the dam wall oppose each other, and so can be cancelled.
But the problem does not ask for the total net force on the dam. It asks for the resultant force exerted by the water on the dam. While the problem author likely intended to ask for the total net force, it is not what they wrote.
 
  • #6
haruspex said:
How did you calculate Pavg?
Thanks for your reply. I found P_avg by assuming the pressure at the top was 1 atm, and the pressure at the bottom was pgH then took the average (divided by 2). Many thanks,
Callum
 
  • #7
Baluncore said:
That one atmosphere is present above the water, through the water column, and also against the dry face of the dam wall. Those two atmospheric forces on the two sides of the dam wall oppose each other, and so can be cancelled.
Thanks, yes, I agree. I just wanted to solve the problem by taking the atmosphere into account then cancelling with Newton's Second Law.
 
  • #8
Callumnc1 said:
and the pressure at the bottom was pgH
Is it though?
 
  • Like
Likes member 731016
  • #9
Orodruin said:
Is it though?
Thanks for your reply, yeah true the pressure is p_0 + pgH which solves my confusion. Thank you very much for pointing that out!
 
  • #10
Orodruin said:
But the problem does not ask for the total net force on the dam. It asks for the resultant force exerted by the water on the dam. While the problem author likely intended to ask for the total net force, it is not what they wrote.
Ok thank you for pointing that out!
 
Back
Top