- #1
CivilSigma
- 227
- 58
I am having trouble with calculating angle theta:
I have derived:
600^2 = [250-150sinx-150cos(40-x)]^2 + [500sin60 + 150cosx +150sin(40-x) ] ^2
how do I solve for x in this case?
I have derived:
600^2 = [250-150sinx-150cos(40-x)]^2 + [500sin60 + 150cosx +150sin(40-x) ] ^2
how do I solve for x in this case?