Solving for area using an integral (intro to parametric curves)

In summary, the problem is to find the area of a region enclosed by the asteroid described by the equations x=a*cos^3\theta and y=a*sin^3\theta. The solution involves using the formula A = \int\sqrt{\frac{dy}{d\theta}^{2}}+\frac{dx}{d\theta}^{2} and plugging in the derivatives of x and y with respect to theta, which can be simplified using the identity cos^2\theta+sin^2\theta =1. The final integral cannot be simplified further, and the region is bounded by the values 0 and pi/2.
  • #1
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Homework Statement


Find the area of the region enclosed by the asteroid:
x=a*cos[tex]^{3}[/tex][tex]\theta[/tex]
y=a*sin[tex]^{3}[/tex][tex]\theta[/tex]

Homework Equations


A = [tex]\int[/tex][tex]\sqrt{\frac{dy}{d\theta}^{2}}+\frac{dx}{d\theta}^{2}[/tex]

The Attempt at a Solution


[tex]\frac{dy}{d\theta}[/tex] = 3asin[tex]^{2}\theta(cos\theta)[/tex]
[tex]\frac{dx}{d\theta}[/tex] = -3acos[tex]^{2}\theta(sin\theta)[/tex]

Plugging that into the equation, I just cannot simplify this integral (sorry ... I tried to write it out but the code got beyond messed up!) from 0 to pi/2! I square them but cannot combine them. Is there an easy way to factor it? Any help you could offer would be greatly appreciated!
 
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  • #2
Try the identity [itex]cos^2\theta+sin^2\theta =1[/itex]
 

FAQ: Solving for area using an integral (intro to parametric curves)

What is an integral?

An integral is a mathematical concept that represents the area under a curve on a graph. It is used to find the total value of a continuous function over a specific interval.

How is an integral used to find the area of a shape?

An integral can be used to find the area of a shape by representing the shape as a continuous function and then finding the area under that function using the integral.

What are parametric curves?

Parametric curves are mathematical functions that are defined by two or more equations, known as parametric equations. These equations describe the relationship between x and y coordinates, allowing for the representation of complex curves and shapes.

How are parametric curves related to solving for area using an integral?

Parametric curves can be used to represent the shape of a curve or region on a graph, and the equations can be used to find the area under the curve. This allows for the use of integrals to find the area of complex shapes that cannot be easily represented by traditional functions.

Are there any limitations to using integrals for finding area using parametric curves?

While integrals can be a powerful tool for finding the area of shapes represented by parametric curves, they may not always be the most efficient method. In some cases, other methods such as geometry or trigonometry may be more suitable for finding the area of a specific shape. It is important to consider the complexity of the shape and the available methods before using integrals for finding area.

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